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April 23rd, 2012, 03:45 AM   #1
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Circular Motion Question!

A car is traveling 10 m/sec on a road where friction is 70% of the car's weight. What is its minimun turning radius?

This is 10th grade physics, thanks for your help!
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April 23rd, 2012, 05:01 AM   #2
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Re: Circular Motion Question!

For this problem you can refer to the case of circular motion. The magnitude of the acceleration is therefore a=-v^2/r.

N II: F=m*a, where no sigma is needed since there is only one force acting in the horizontal plane.

So, now you have:

-0.7mg=m*a=-mv^2/r (negative sign on the left-hand-side of the equation since the positive direction points outward for polar coordinates.)

In the above expression I have used the fact that the friction force is 70% of the cars weight, mg, along with the fact that it is a good approximation to assume the friction force to be the only force acting in the horizontal plane.

The mass must not be zero for the problem to have a physical meaning, so it is safe to divide the expression by -m:

0.7g=v^2/r

r=v^2/(0.7g)

And there is your answer.
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