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March 31st, 2012, 06:41 AM   #1
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Torque

I've been stuck on the same question for hours now, please help!!

A ladder stands up against a wall. There is no friction between the wall and the ladder. The "gravity force" on the ladder is 50N and it is 4m long. How big is the force N? (see attached image)
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 March 31st, 2012, 08:13 AM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs Re: Torque Let w be the weight and L be the length of the ladder. Let ? be the angle of the ladder above the horizontal. When the torques are taken about the origin O at the bottom of the ladder, we get: $\sum \tau_O=NL\sin$$\theta$$-w\frac{L}{2}\cos$$\theta$$=0$ Solving for N we find: $N=\frac{w}{2}\cot$$\theta$$$

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### torque of ladder against wall

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