January 30th, 2012, 09:19 PM  #1 
Newbie Joined: Nov 2011 Posts: 17 Thanks: 0  Dimensional analysis (Weir Eq.)
So Code: Q=3.33(L0.2h)(h)^1.5 I know the answer should be Code: Q=1.84(L0.2h)(h)^1.5 Some help would be appreciated, thank you. 
January 30th, 2012, 09:51 PM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: Dimensional analysis (Weir Eq.)
I know that 2.54 cm = 1 in exactly, thus: thus: For your regular contracted weir, the discharge coefficient must have units of and so our conversion factor is: and we find: 
January 30th, 2012, 10:15 PM  #3 
Newbie Joined: Nov 2011 Posts: 17 Thanks: 0  Re: Dimensional analysis (Weir Eq.)
Ah thanks, that did it. This problem's a little harder, was wondering how you would tackle it. I found the conversion for each unit from Enlight Engineering units to CGS units: Code: psi > g/cm*s^2 = 68948 lb/gal > g/cm*s^3 = 0.1198 in > cm = 2.54 ft/sec > cm/s = 30.48 ft > cm = 30.48 cp > g/cm*s = 0.01 
January 30th, 2012, 10:15 PM  #4 
Newbie Joined: Nov 2011 Posts: 17 Thanks: 0  Re: Dimensional analysis (Weir Eq.)
Forgot pic woops 
February 6th, 2012, 06:56 PM  #5 
Newbie Joined: Nov 2011 Posts: 17 Thanks: 0  Re: Dimensional analysis (Weir Eq.)
Any help with my last question?

February 6th, 2012, 08:05 PM  #6 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs  Re: Dimensional analysis (Weir Eq.)
We would need: ^{0.75}(30.4^{1.75}(30.4(0.01)^{ 0.25}}{(2.54 )^{1.25}}\approx242.014627124" /> 
February 6th, 2012, 08:13 PM  #7  
Newbie Joined: Nov 2011 Posts: 17 Thanks: 0  Re: Dimensional analysis (Weir Eq.) Quote:
for the attached image, does this look right? ?Pf = mupLv / (1.2x10^3)(d0di)^2 + YbL / (.065)(d0di)  

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