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December 7th, 2010, 07:45 PM   #1
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Equilibrium

2SO3 + heat <-> 2SO2 + O2
A 4 liter container originally contains 0.6 moles of . At Equilibrium 0.12 moles of had been produced. Calculate

I was arguing with someone else over how this problem is done. Here is how I did it.

[SO3]=0.6-0.12=0.48
[O2]=0.12

So since 2SO2: SO2=2[O2]=2(0.12)=0.24
[SO3]=0.6-0.12=0.48-0.24=0.24
[SO2]=0.24
[O2]=0.12






Am I right?
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December 8th, 2010, 06:11 AM   #2
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Re: Equilibrium

i think u r right except for one important thing :
in the formula of computing keq u should use concentrations not quantities so u should actually have had C(O2)=.12/4=0.03
C(so3)=0.24/4=0.06
C(SO2)=0.24/4=0.06 (C means concentration which is quantity / volume)
then keq=0.03=3*10^(-2)
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December 8th, 2010, 02:35 PM   #3
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Re: Equilibrium

I thought of that during school today. I guess we were both wrong, he forgot about the ratio.
I also wrote K=12x10^-2, not scientific notation. K=1.2x10^-1

Thank you for your help.
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