 My Math Forum Finding the acceleration of two masses with gravity relati..
 User Name Remember Me? Password

 Physics Physics Forum

 March 17th, 2010, 07:17 PM #1 Member   Joined: Jul 2009 Posts: 57 Thanks: 0 Finding the acceleration of two masses with gravity relati.. Title limit: Finding the acceleration of two masses with gravity relative to a fixed grid/or-point. Funny, as soon as I go to post this, I see a post by dedanoe stating errors about newton's G. If he is right, I may already be at fault. But here is what I did to find the force between to masses, A (m_1) 8kg, B (m_2) 4kg, at a distance of 2m: Code:  6.67 x 10^-11 m^3 G = ----------------- kg * s^2 m_1 * m_2 F = G * ------------- r^2 m_1 = 8kg m_2 = 4kg r = 2m Thus: [6.67 x 10^-11m^3] [8kg * 4kg] F = [----------------] * [---------] [ kg * s^2 ] [ (2m)^2 ] = [6.67 x 10^-11m^3] [ 32kg^2 ] F = [----------------] * [--------] [ kg * s^2 ] [ 4m^2 ] = [2.13 x 10^-9m^3 * kg^2] F = [----------------------] [ 4m^2 * kg * s^2 ] = [2.13 x 10^-9m^3 * kg^2] F = [----------------------] [ 4m^2 * kg * s^2 ] = [5.33 x 10^-10m^3 * kg^2] F = [-----------------------] [ m^2 * kg * s^2 ] = [5.33 x 10^-10m * kg] | [kg * m] [kg * m] F = [-------------------] | 1 N = 1 * [------] 5.33 x 10^-10 N = 0.000000000533 * [------] [ s^2 ] | [ s^2 ], [ s^2 ] If I have made no errors the force should be 5.33 x 10^-10 N. What I want to find now is the acceleration on each object unique to another fixed point at which defines their state. If a = f/m then it should be correct to say for mass A, that a = (5.33 x 10^-10 N)/8kg. But isn't this is the acceleration of mass A, (to the fixed point I just defined), as if B was fixed? How would I find out the acceleration of both objects? It would be correct to say that mass B will have greater acceleration than mass A. right? Thanks. March 18th, 2010, 05:41 PM #2 Member   Joined: Jul 2009 Posts: 57 Thanks: 0 Re: Finding the acceleration of two masses with gravity relati.. Never mind. I was doing it wrong. Just found this: http://www-istp.gsfc.nasa.gov/stargaze/Sgravity.htm Helped me out a bit. I was doing it separately. Being that F = ma, and G(m m2)/r^2 = F; m G(m2)/r^2 = ma = G(m2)/r^2 = a, ("a" usually as "g".) Which allowed me to find the earths acceleration to be ~9.81[...]m/s^2. Thanks. Tags acceleration, finding, gravity, masses, relati ,

### finding acceleration of packing crates

Click on a term to search for related topics.
 Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post inkliing Physics 0 December 16th, 2013 11:40 PM micle Physics 1 June 17th, 2013 10:17 PM DPXJube Physics 1 January 28th, 2012 07:32 PM r-soy Physics 2 December 11th, 2010 08:09 AM JosephE Algebra 2 November 28th, 2009 08:44 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top      