July 30th, 2009, 11:26 PM  #1 
Newbie Joined: Jul 2009 Posts: 1 Thanks: 0  Reverse Modulo
Hi, I have a little question. Is there a quick way to evaluate the smallest number (x) that matches the following condition? x modulo a = e x modulo b = f a, b, e and f are given and I want to compute the smallest or if that is not possible any number (x) that matches that condition. Example: x modulo 5 = 4 x modulo 7 = 5 The smallest number that matches that condition is 19. Other values are 54, 89,... My current solution is working like this 4 5 > (4 < 5) > 4+5 9 5 > (9 > 5) > 5+7 9 12 > (9 < 12) > 9+5 14 12 > (14 > 12) > 12+7 14 19 > (14 < 19) > 14+5 19 19 > (19 = 19) > finished But that seems kind of slow. 
August 5th, 2009, 10:12 PM  #2 
Newbie Joined: Jul 2009 Posts: 21 Thanks: 0  Re: Reverse Modulo
The problem is you forgot to remove the = when there are over 3 separate numbers in it. Try dat. <3 
August 6th, 2009, 04:53 AM  #3 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: Reverse Modulo
You need Sunzi's theorem (the "Chinese remainder theorem"). I can't tell (!) if that's what you're doing above. Personally, I use Code: chinese(Mod(4, 5), Mod(5, 7)) 

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