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April 2nd, 2015, 08:38 AM   #51
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Math Focus: pi,prime numbers,random function
Prime Numbers: probability of primes between two even number

probability of prime between two odd number is given by
d(2*n-2)/d(2*n+2) n belongs to natural number.
if the ratio is in the range of 0.8 to 0.9 it is called lucky prime number.

d^2(2*n-2)/d^2(2*n+2) also could be used.
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April 2nd, 2015, 08:41 AM   #52
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using 2,3,5 making 9 digit pi

10/3,11/7,12/4(3/1),13/8,14/9,15/9,6,7/2,8/5



2*5=10
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April 2nd, 2015, 08:44 AM   #53
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keep discovering

keep discovering , because there is lot to be discover.
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April 2nd, 2015, 08:16 PM   #54
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Math Focus: pi,prime numbers,random function
PI need help to invent formula

$\displaystyle 1/π=(√3-√2)√(2^9&log_5⁡〖((27√2-4√3)/〖(0.999)〗^2 〗 √(2^22&(cos⁡(k^0))/130))$


need help to calculate k.
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April 2nd, 2015, 08:20 PM   #55
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PI need help to invent formula

Code:
1/π=(√3-√2)√(2^9&log_5⁡〖((27√2-4√3)/〖(0.999)〗^2 〗 √(2^22&(cos⁡(k^0))/130))
need help to calculate k.
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April 2nd, 2015, 09:02 PM   #56
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Math Focus: pi,prime numbers,random function
Goldbach Conjecture:using Random function

Goldbatch Conjecture states that every even integer greater than 2 can be expressed as the sum of two primes.
the number of ways in which 2n can be writtern as the sum of two two primes
0,1,1,1,2,1,2,2,2,2,3,3,3,2,3,2,4

this number of possibilties is found to be equal to J^2(2n) very close to it.
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April 2nd, 2015, 09:02 PM   #57
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Math Focus: pi,prime numbers,random function
Goldbach Conjecture:using Random function

Goldbatch Conjecture states that every even integer greater than 2 can be expressed as the sum of two primes.
the number of ways in which 2n can be writtern as the sum of two two primes
0,1,1,1,2,1,2,2,2,2,3,3,3,2,3,2,4

this number of possibilties is found to be equal to
$\displaystyle $\displaystyle J^2(2n) $$
very close to it.
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April 2nd, 2015, 09:19 PM   #58
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Random Euler's number

random euler number could be produced by god function

(n-1)^(1/d(n-1))+(n+1)^(1/d(n+1))

where d(n-1),d(n+1) is god function
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April 2nd, 2015, 09:30 PM   #59
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Quote:
Originally Posted by Rahul k View Post
random euler number could be produced by god function

(n-1)^(1/d(n-1))+(n+1)^(1/d(n+1))

where d(n-1),d(n+1) is god function
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April 3rd, 2015, 01:07 AM   #60
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Please use standard punctuation characters, such as "(", "[", or "{", as your posts contain dozens of characters that don't show as anything meaningful for most people. For example, you posted "1/π=(√3-√2)√(2^9&log_5##((27√2-4√3)/#(0.999)#^2 # √(2^22&(cos#(k^0))/130))", where each such character has been replaced by "#" to draw your attention. For this and other reasons, the substantial majority of your posts are incomprehensible, even to those who are particularly interested in primes.
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