November 21st, 2014, 10:16 AM  #21 
Senior Member Joined: Nov 2013 From: Germany Posts: 179 Thanks: 1 Math Focus: Number Theory 
So I have a new one : $\displaystyle (n^21)^2+(2n)^2=(n^2+1)^2$ Now its perfect! M_B_S 
November 21st, 2014, 10:33 AM  #22 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,696 Thanks: 2681 Math Focus: Mainly analysis and algebra 
Apart from the list of Pythagorean triples (such as 5, 12, 13) that it can't generate.

November 21st, 2014, 01:50 PM  #23 
Senior Member Joined: Nov 2013 From: Germany Posts: 179 Thanks: 1 Math Focus: Number Theory  
November 21st, 2014, 02:36 PM  #24 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,696 Thanks: 2681 Math Focus: Mainly analysis and algebra 
That has at most two solutions.
Last edited by v8archie; November 21st, 2014 at 02:38 PM. 
November 21st, 2014, 03:54 PM  #25 
Member Joined: Oct 2014 From: Lublin, POLAND Posts: 30 Thanks: 3  the new triple? 

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