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June 28th, 2014, 08:11 AM  #1 
Senior Member Joined: Nov 2013 From: Germany Posts: 179 Thanks: 1 Math Focus: Number Theory  All Pythagorean Triples cÂ²=aÂ²+bÂ² here
(2ab)Â² + (aÂ²bÂ²)Â²= (aÂ²+bÂ²)Â² ab = n in N q.e.d. M_B_S 
June 29th, 2014, 01:36 PM  #2 
Senior Member Joined: Sep 2012 From: British Columbia, Canada Posts: 764 Thanks: 53 
This is just Euclid's formula to generate Pythagorean triples.

July 2nd, 2014, 12:39 AM  #3  
Senior Member Joined: Nov 2013 From: Germany Posts: 179 Thanks: 1 Math Focus: Number Theory  Not all Quote:
(k2ab)Â²+(k(aÂ²bÂ²))Â²=(k(aÂ²+bÂ²)Â² it comes from 4ab=(a+b)Â²(ab)Â² Physics intuitions: A Pythagorean relation for any triangle?  

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