My Math Forum Bad "Proof" of Fermat's Last explained (in 3-5 minutes)

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 April 26th, 2014, 11:08 AM #1 Newbie   Joined: Apr 2014 From: USA Posts: 11 Thanks: 0 Bad "Proof" of Fermat's Last explained (in 3-5 minutes) I had to comment on the error in a closed post. The argument boiled down to: $\displaystyle z = (C^n - B^n)/(A^{n-2})$ where z is an integer. The post claimed this is an immediate contradiction as the GCD of A, B, and C are 1. I can find many examples of (A, B, C, z) that work for n = 3. Simply let A = C - B where gcd(B, C) = 1 Examples: $\displaystyle 9^3 - 4^3$ is divisible by $\displaystyle 5^1$. $\displaystyle 23^3 - 7^3$ is divisible by $\displaystyle 16^1$. Suppose you want a counterexample for n > 3. If n = 11, we see that: $\displaystyle (A = 2^9, B = 1001, C = 1001 + 2^9, z = (C^{11} - B^{11})/(2^9))$ is a perfectly good counterexample. -- MMG Last edited by mobilemathguy; April 26th, 2014 at 11:11 AM.

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