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November 10th, 2013, 02:28 AM   #1
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The last two digits of LARGE numbers?

Hello,
can i get help with this?
for example:
34^27^48

in this example we need the x:
34^27^48 congruent x (mod 100)

And one more question:Is this correct?(the picture)
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November 10th, 2013, 05:35 AM   #2
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Re: The last two digits of LARGE numbers?

Quote:
Originally Posted by ricsi046
Is this correct?(the picture)
Yes. You can use the same approach with 34^27^48.
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November 10th, 2013, 06:31 AM   #3
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Re: The last two digits of LARGE numbers?

ok i will try it thanks
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