My Math Forum The last two digits of LARGE numbers?

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November 10th, 2013, 01:28 AM   #1
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The last two digits of LARGE numbers?

Hello,
can i get help with this?
for example:
34^27^48

in this example we need the x:
34^27^48 congruent x (mod 100)

And one more question:Is this correct?(the picture)
Attached Images
 cong.png (10.5 KB, 171 views)

November 10th, 2013, 04:35 AM   #2
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Re: The last two digits of LARGE numbers?

Quote:
 Originally Posted by ricsi046 Is this correct?(the picture)
Yes. You can use the same approach with 34^27^48.

 November 10th, 2013, 05:31 AM #3 Member   Joined: Sep 2013 Posts: 84 Thanks: 2 Re: The last two digits of LARGE numbers? ok i will try it thanks

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