 My Math Forum For what natural n is the number (5^(2*n+1))*(2^(n+2))+(3^(n+2))+(2^(2*n+1)) divisibl
 User Name Remember Me? Password

 Number Theory Number Theory Math Forum

 July 1st, 2019, 07:39 AM #1 Newbie   Joined: Jun 2019 From: London Posts: 13 Thanks: 0 For what natural n is the number (5^(2*n+1))*(2^(n+2))+(3^(n+2))+(2^(2*n+1)) divisibl For what natural n is the number (5^(2*n+1))*(2^(n+2))+(3^(n+2))+(2^(2*n+1)) divisible by 19? I get that (19*(50^n + 12^n) + (50-19)(50^n +....+19^n). So it means that n can be any natural number? Or I did some mistake there? Last edited by skipjack; July 1st, 2019 at 03:57 PM. July 1st, 2019, 04:03 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,965 Thanks: 2214 You definitely made a mistake, as your parentheses aren't paired correctly. The original expression seems to be divisible by 19 for n = 12, 30, 48, etc. Tags 12n, 22n, 52n, divisibl, math, natural, number, number theory Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post panky Algebra 4 May 20th, 2016 03:53 AM zylo Topology 13 February 18th, 2016 08:07 AM ManInTheSuit New Users 4 June 2nd, 2015 05:48 AM Shen Elementary Math 2 June 5th, 2014 07:50 AM johnny Calculus 3 March 7th, 2011 08:02 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top       