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  • 2 Post By Collag3n
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May 21st, 2019, 08:53 PM   #1
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Joined: May 2015
From: Arlington, VA

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Math Focus: Number theory
1, 2, 3... sum/product summation

Loren is offline  
May 22nd, 2019, 03:28 AM   #2
Joined: Sep 2017
From: Belgium

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by using this
$\sum_{k=0}^\infty{k+2\choose k}\frac{1}{(k+1)!}$
$\sum_{k=0}^\infty\frac{k+2}{2\cdot k!}$
$\sum_{k=0}^\infty\frac{k}{2\cdot k!}+\frac{1}{k!}$
and this
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sum or product, summation

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