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April 22nd, 2019, 10:42 AM  #1 
Senior Member Joined: Mar 2019 From: iran Posts: 318 Thanks: 14  largest number using 0 to 9 digits without using two consecutive factorial
is it the largest number? (0!+12)^3!^4!^5!^6!^7!^8!^9! 
April 22nd, 2019, 12:00 PM  #2 
Senior Member Joined: Aug 2012 Posts: 2,357 Thanks: 740 
Henny Youngmath. Take my wff. Please!

April 22nd, 2019, 01:32 PM  #3 
Senior Member Joined: Dec 2015 From: somewhere Posts: 605 Thanks: 88  
April 22nd, 2019, 01:40 PM  #4  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038  Quote:
must digits be in ascending/descending/whatever order? you're showing (0! + 12) : 12 is not a digit; problem seems to say "using each digit once and by itself..." Is 8! * 9! considered as two consecutive factorials? There is a * between them... Edit: whadda hell is a "wff" ??? ; I'm used to "wtf" Last edited by Denis; April 22nd, 2019 at 01:42 PM.  
April 22nd, 2019, 02:17 PM  #5 
Senior Member Joined: Dec 2015 From: somewhere Posts: 605 Thanks: 88 
Exponential tetration gives the largest number using the rules you gave. https://en.wikipedia.org/wiki/Tetration 
April 22nd, 2019, 06:39 PM  #6 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 
From Tetration to Titration ?? Sounds like Old McDonald switching from machine milking to milking by hand!! Last edited by Denis; April 22nd, 2019 at 06:46 PM. 
April 23rd, 2019, 08:50 AM  #7 
Senior Member Joined: Jun 2014 From: USA Posts: 528 Thanks: 43  

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consecutive, digits, factorial, largest, number 
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