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 April 22nd, 2019, 10:42 AM #1 Senior Member   Joined: Mar 2019 From: iran Posts: 318 Thanks: 14 largest number using 0 to 9 digits without using two consecutive factorial is it the largest number? (0!+12)^3!^4!^5!^6!^7!^8!^9!
 April 22nd, 2019, 12:00 PM #2 Senior Member   Joined: Aug 2012 Posts: 2,357 Thanks: 740 Henny Youngmath. Take my wff. Please! Thanks from idontknow
April 22nd, 2019, 01:32 PM   #3
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Quote:
 Originally Posted by Maschke Henny Youngmath. Take my wff. Please!
Take mine too.

April 22nd, 2019, 01:40 PM   #4
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Quote:
 Originally Posted by youngmath largest number using 0 to 9 digits without using two consecutive factorial; is it the largest number? (0!+12)^3!^4!^5!^6!^7!^8!^9!
Unclear!
must digits be in ascending/descending/whatever order?
you're showing (0! + 12) : 12 is not a digit;
problem seems to say "using each digit once and by itself..."

Is 8! * 9! considered as two consecutive factorials?
There is a * between them...

Edit: whadda hell is a "wff" ??? ; I'm used to "wtf"

Last edited by Denis; April 22nd, 2019 at 01:42 PM.

 April 22nd, 2019, 02:17 PM #5 Senior Member   Joined: Dec 2015 From: somewhere Posts: 605 Thanks: 88 Exponential tetration gives the largest number using the rules you gave. https://en.wikipedia.org/wiki/Tetration
 April 22nd, 2019, 06:39 PM #6 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 From Tetration to Titration ?? Sounds like Old McDonald switching from machine milking to milking by hand!! Thanks from idontknow Last edited by Denis; April 22nd, 2019 at 06:46 PM.
April 23rd, 2019, 08:50 AM   #7
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Quote:
 Originally Posted by Maschke Henny Youngmath. Take my wff. Please!
Re: WFF

 Tags consecutive, digits, factorial, largest, number

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