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April 22nd, 2019, 10:42 AM   #1
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largest number using 0 to 9 digits without using two consecutive factorial

is it the largest number?
(0!+12)^3!^4!^5!^6!^7!^8!^9!
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April 22nd, 2019, 12:00 PM   #2
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Henny Youngmath. Take my wff. Please!
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April 22nd, 2019, 01:32 PM   #3
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Quote:
Originally Posted by Maschke View Post
Henny Youngmath. Take my wff. Please!
Take mine too.
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April 22nd, 2019, 01:40 PM   #4
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Quote:
Originally Posted by youngmath View Post
largest number using 0 to 9 digits without using two consecutive factorial;
is it the largest number?
(0!+12)^3!^4!^5!^6!^7!^8!^9!
Unclear!
must digits be in ascending/descending/whatever order?
you're showing (0! + 12) : 12 is not a digit;
problem seems to say "using each digit once and by itself..."

Is 8! * 9! considered as two consecutive factorials?
There is a * between them...

Edit: whadda hell is a "wff" ??? ; I'm used to "wtf"

Last edited by Denis; April 22nd, 2019 at 01:42 PM.
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April 22nd, 2019, 02:17 PM   #5
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Exponential tetration gives the largest number using the rules you gave.
https://en.wikipedia.org/wiki/Tetration
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April 22nd, 2019, 06:39 PM   #6
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From Tetration to Titration ??

Sounds like Old McDonald switching
from machine milking to milking by hand!!
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Last edited by Denis; April 22nd, 2019 at 06:46 PM.
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April 23rd, 2019, 08:50 AM   #7
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Quote:
Originally Posted by Maschke View Post
Henny Youngmath. Take my wff. Please!
Re: WFF

https://www.google.com/amp/s/www.urb...f%26amp%3Dtrue
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