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May 10th, 2019, 11:02 PM   #31
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Originally Posted by youngmath View Post
ok the first equation is true for positive x and y and positive n > 1
the second equation is true for positive x and y and positive n > 2
If you have a proof for (2) then someone -- I wish it didn't have to be me but I'm in for a penny in for a pound in this thread -- will have to work through the algebra to find the mistake.

@michaelweir We know there's a mistake because we saw a few days back that no proof based on elementary algebraic manipulations can work. And there's the meta-reason that if there were in fact an elementary algebraic proof, someone would have found it in 350 years.

So there is a mistake in there, and I was hoping (1) or (2) would be false, but if they are both true then somebody needs to dive in. Any volunteers?

Last edited by Maschke; May 10th, 2019 at 11:05 PM.
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May 11th, 2019, 08:35 AM   #32
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the post #2 shows the proof and the final result are wrong

Last edited by youngmath; May 11th, 2019 at 08:46 AM.
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May 13th, 2019, 11:11 AM   #33
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Masche - Thank you for spending the time you have spent on this proof. I THINK YOU WILL BE REWARDED FOR SPENDING THE TIME. I haven't spent the time to rebut the argument to show that proof is outside the parameters of an algebraic manipulation, as is this one. To make the claim that this proof about algebraic applies you will have to label every statement in a proof is an example of a algebraic manipulation. I don't think you can do that.

The Nautilus construction is much more than a way to solve FLT. I have come up with a way to combine the number line analysis of this proof with the Nautilus to come up with another FLT. There are probably other proofs of FLT using the Nautilus. It's like using a fishing net of the ocean of Mathematics, instead of a single fishing line. Who knows what fish will be caught next?

Last edited by skipjack; June 4th, 2019 at 02:30 PM.
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June 4th, 2019, 01:59 PM   #34
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Just saying something doesn't make it right. I ignored replying until now, to see if you would have something to say. You didn't. Nor has anyone else made any comments. So, am I right in believing that the proof is right?
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June 4th, 2019, 02:29 PM   #35
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I can't speak for anyone else but I think the silence is more likely that we've given up on your "simple" approach to a problem that has been proven not to have one.

-Dan
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June 4th, 2019, 03:05 PM   #36
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in the second pdf equation 5 is wrong because you wrote e/f*h instead of e/f*h*y
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June 6th, 2019, 04:15 PM   #37
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youngmath
Yes i made an error in equation 4, where I should have factored the Y out then. So, th error was corrected by taking it out equation 5. So the proof is still good.

I am looking for someone to help me with writing the proof in an acceptable from to submit to a mathmatical journal. I will share credit and prizes with whoever helps.
the field medal is worth $700,000 at leqst.
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June 6th, 2019, 06:01 PM   #38
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equation 3
h*y*(c^2/d^2 * h * y - 2 c/d * y - e/f * h * y) = -2 y^2
multiply h*y by the bracket in LHS
h^2 * y^2 * c^2/d^2 - 2 * h * y^2 * c/d - h^2 * y^2 * e/f = -2 y^2
factor y^2 out of both sides
h^2 * c^2/d^2 - 2 * h * c/d - h^2 * e/f = -2
as you see y doesn't remain in the equation
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June 6th, 2019, 06:39 PM   #39
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https://www.wolframalpha.com/input/?...-2+y%5E2+for+y
Equation simplifies to:
y^2(c^2*h^2/d^2 - 2*c*h/d - e*h^2/f + 2)=0

Last edited by Denis; June 6th, 2019 at 06:51 PM.
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June 6th, 2019, 07:58 PM   #40
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Quote:
Originally Posted by michaelcweir View Post
...writing the proof in an acceptable from to submit to a mathmatical journal.
Well, the first step for that would be to learn how to use $\LaTeX$. If you wrote your post in latex you would be able to copy paste into a latex document. Also, if you rewrote your post with it i'm sure a lot more people would be willing to read through it since it wouldn't be a haphazard mess of "*"s and "^"'s.
Thanks from Denis and topsquark
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