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January 3rd, 2019, 12:19 PM   #51
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Originally Posted by JeffM1 View Post
So his uniqueness argument is not merely unproven, but unprovable and unnecessary. ROFL
Problem is, you can't convince him of this, since he argues by contradiction...

You can come up with a different kind of algebraic structure where there are provably finitely many twin primes, and show his argument fails there. Or you can do like collag3n above and consider teta-primes to show his argument fails. But he doesn't understand those, so he will dismiss it.

By the way, you might be interested in a simple proof of Bael's conjecture, also very hilarious: The Simple Proof of Beal's Conjecture - xkcd
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January 3rd, 2019, 12:24 PM   #52
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Doesn't seem like the OP had much luck publishing his revolutionary results: https://www.ams.org/editflow/ef/stat...&cr=A394166B12
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January 3rd, 2019, 12:28 PM   #53
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You are all making a very simple explanation of the truth of the twin prime conjecture over complicated probably because the maths gurus like Field medalist, Terence Tao have made the twin prime conjecture a big deal when really it is not. My proof is just as logical and as simple as proving the infinitude of primes. My proof uses the sieve of Eratosthenes, which by the way is the algorithmic generator of the primes, to show the infinitude of twin primes. I have shown that the sieve of Eratosthenes cannot 'hit' all the 6n-1 and 6n+1 pairs using a simple proof. This sieve operates by giving every prime greater than 3 opportunities to eliminate 6n-1 and 6n+1 pairs. It is agreed that each prime in its infinite hopping will hop over an infinite number of un-eliminated 6n-1and 6n+1 pairs and therefore no one prime can eliminate all infinite number of 6n-1 and 6n+1 pairs. This means that the twin primes will never run out.

Read my post top of page 5 (if you didn't catch the flaw in the previous post I made): none of my teta-primes can eliminates all teta-twins (they eliminate a infinitely small portion of them at each step), there are still an infinite of teta-twins at each step but in the end, there is NO teta-twin at all. NONE !!!! But the reasoning is exactly the one you have. Can you explain why ? (this is basic math, no need to be Terence)
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January 3rd, 2019, 12:30 PM   #54
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Doesn't seem like the OP had much luck publishing his revolutionary results: https://www.ams.org/editflow/ef/stat...&cr=A394166B12
Ouch! That one has to sting.

I've never heard of this site. I like it!

-Dan
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January 3rd, 2019, 12:30 PM   #55
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Read my post top of page 5 (if you didn't catch the flaw in the previous post I made): none of my teta-primes can eliminates all teta-twins (they eliminate a infinitely small portion of them at each step), there are still an infinite of teta-twins at each step but in the end, there is NO teta-twin at all. NONE !!!! But the reasoning is exactly the one you have. Can you explain why ? (this is basic math, no need to be Terence)
Smart argument! But don't bother, the OP won't understand the relevance of your example. He's been pushing this exact proof for 9 years already Proof of the Twin Prime Conjecture - xkcd
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January 3rd, 2019, 02:55 PM   #56
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At least I Tried

Ok, look again at my sieve (top of page 5). There is no way any of my teta-prime can eliminate all teta-twins. They NEVER RUN OUT like you say. At each step and forever, despite the infinite number of teta-multiples sieved, there will be infinitely many teta-twin candidates left.

You would think there are infinitely many teta-twins. Nonetheless I dare you to give me 1 (only 1) example of teta-twin that will never be sieved.
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