My Math Forum Find the number of possible choices for x and y when A=100?

 Number Theory Number Theory Math Forum

 June 16th, 2018, 07:26 AM #1 Newbie   Joined: Jun 2018 From: Nepal Posts: 3 Thanks: 0 Find the number of possible choices for x and y when A=100? I have some questions during the writing of this post, please read it via https://www.physicslog.com/number-of-choices/
 July 4th, 2018, 11:56 PM #2 Member   Joined: Aug 2015 From: Chiddingfold, Surrey Posts: 50 Thanks: 3 Math Focus: Number theory, Applied maths I agree with your answer = 49 and think your algorithm is OK for any value of A. Hope you get more replies to this and your other questions with A being the sum of more than two different numbers/ Thanks from topsquark
 July 7th, 2018, 04:25 PM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,244 Thanks: 887 Yes, there are 49. The positive integer pairs, (x, y), such that x+ y= 100 are (1, 19), (2, 98 ), (3, 97), ... (97, 3), (98, 2), (99, 1). My first thought was that there were 99 such pairs but then I noticed the conditions that $x\ne y$ and that order is not to be considered. Dropping the pair (50, 50) leave 98 pairs and half of that is 49. Thanks from topsquark
 July 16th, 2018, 01:49 AM #4 Newbie   Joined: Aug 2015 From: Montenegro (Podgorica) Posts: 20 Thanks: 2 If you include the pair 0 + 100 = 100, then you have a half pairs for even, and half - 1 pairs for odd. Last edited by skipjack; July 16th, 2018 at 03:45 AM.

 Tags a100, choices, find, number

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post policer Probability and Statistics 5 December 27th, 2017 09:19 AM BookInquiry Math Books 7 June 4th, 2014 10:59 PM Lupeto Applied Math 0 November 6th, 2010 02:48 AM jsonliu Algebra 3 May 18th, 2010 05:01 PM astrix Advanced Statistics 1 August 25th, 2009 05:11 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top