March 30th, 2018, 09:45 AM  #1 
Newbie Joined: Mar 2018 From: California Posts: 18 Thanks: 0  A Problem
Solve in positive integers $x^3+y^3+3xyz=z^3+2018$ This problem doesn't seem to be solvable because there are three variables in one equation. Could anyone provide some assistance? Please provide full solutions with justifications. 
March 30th, 2018, 01:00 PM  #2 
Newbie Joined: Sep 2017 From: Belgium Posts: 8 Thanks: 2 
$(x+yz)\cdot(x^2+y^2+z^2xy+xz+yz)=2\cdot1009$
