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 March 30th, 2018, 09:45 AM #1 Newbie   Joined: Mar 2018 From: California Posts: 18 Thanks: 0 A Problem Solve in positive integers $x^3+y^3+3xyz=z^3+2018$ This problem doesn't seem to be solvable because there are three variables in one equation. Could anyone provide some assistance? Please provide full solutions with justifications.
 March 30th, 2018, 01:00 PM #2 Newbie   Joined: Sep 2017 From: Belgium Posts: 4 Thanks: 2 $(x+y-z)\cdot(x^2+y^2+z^2-xy+xz+yz)=2\cdot1009$ Thanks from greg1313 and JeffM1

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