Relative Mathematics In every R there exists an integer zero element ( 0 ) ( 0 ) =/= 0 0 = (0) ( 0 ) : possesses the additive identity property ( 0 ) : does not possess the multiplication property of 0 ( 0 ) : possesses the multiplicative identity property of 1 The zero elements ( 0 ) and ( 0 ) in an expression of division can only exist as: (0)/( 0 ) 0 + ( 0 ) = 0 = ( 0 ) + 0 ( 0 ) + ( 0 ) = 0 1 + ( 0 ) = 1 = ( 0 ) + 1 0 * ( 0 ) = 0 = ( 0 ) * 0 1 * ( 0 ) = 1 = ( 0 ) * 1 n * ( 0 ) = n = ( 0 ) * n Therefore, the zero element ( 0 ) is by definition also the multiplicative inverse of 1 . And as division by the zero elements requires (  0 ) as the divisor ( x / ( 0 )) is defined as the quotient ( x ) . 0 / n = 0 0 / ( 0 ) = 0 n / ( 0 ) = n 0 / 1 = 0 1 / ( 0 ) = 1 1 / 1 = 1 ( 1/( 0 ) = 1 ) The reciprocal of ( 0 ) is defined as 1/( 0 ) 1/(0) * ( 0 ) = 1 (0)^(1) = ( 1/( 0 ) = 1 (0)(0)^(1) = 1 = ( 0 )^(1) Any element raised to ( 1 ) equals that elements inverse. 0^0 = undefined 0^(0) = undefined 1^0 = 1 1^(0) = 1 Therefore, all expressions of ( 0 ) or ( 0 ) as exponents or as logarithms are required to exist without change. Therefore, division by zero is defined. Therefore, the product of multiplication by zero is relative to which integer zero is used in the binary expression of multiplication. Transitivity is not applicable to the additive identity elements. 
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And yet again you fail to answer the point that I made. http://mymathforum.com/numbertheory...tml#post585359 
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As I disagree with you on both accounts. Nothing further is needed between us. 
Hey.. Déjà vu 
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Do you have a point? I would listen to all you share carefully just as I did with v8archie......further if I cared I could provide links to other forums with this...where people agree his point is "pointless"...I will not do so...I will move on....perhaps you should do the same...in whatever direction that takes you... but passive aggressive replies are not the answer. 
Ah, we're not attempting to do mathematics any more. This is all makebelieve. 
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Is this a new number ?  Mathematics  Science Forums 
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Please note I stated for all in this thread "A New Relative Mathematics" "That this is a exercise in theory. And nothing more" Perhaps in light of this you should give me a break. 
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