December 4th, 2017, 10:03 PM  #1 
Banned Camp Joined: Aug 2012 Posts: 153 Thanks: 3  A New Relative Mathematics Relative Mathematics In every R there exists an integer zero element ( 0 ) ( 0 ) = 0 ( 0 ) : possesses the additive identity property ( 0 ) : does not possess the multiplication property of 0 ( 0 ) : possesses the multiplicative identity property of 1 The zero elements ( 0 ) and ( 0 ) in an expression of division can only exist as: (0)/( 0 ) 0 + ( 0 ) = 0 = ( 0 ) + 0 ( 0 ) + ( 0 ) = 0 1 + ( 0 ) = 1 = ( 0 ) + 1 0 * ( 0 ) = 0 = ( 0 ) * 0 1 * ( 0 ) = 1 = ( 0 ) * 1 n * ( 0 ) = n = ( 0 ) * n Therefore, the zero element ( 0 ) is by definition also the multiplicative inverse of 1 . And as division by the zero elements requires (  0 ) as the divisor ( x / ( 0 )) is defined as the quotient ( x ) . 0 / n = 0 0 / ( 0 ) = 0 n / ( 0 ) = n 0 / 1 = 0 1 / ( 0 ) = 1 1 / 1 = 1 ( 1/( 0 ) = 1 ) The reciprocal of ( 0 ) is defined as 1/( 0 ) 1/(0) * ( 0 ) = 1 (0)^(1) = ( 1/( 0 ) = 1 (0)(0)^(1) = 1 = ( 0 )^(1) Any element raised to ( 1 ) equals that elements inverse. 0^0 = undefined 0^(0) = undefined 1^0 = 1 1^(0) = 1 Therefore, all expressions of ( 0 ) or ( 0 ) as exponents or as logarithms are required to exist without change. Therefore, division by zero is defined. Therefore, the product of multiplication by zero is relative to which integer zero is used in the binary expression of multiplication. 
December 5th, 2017, 06:26 AM  #2 
Newbie Joined: Nov 2017 From: US Posts: 5 Thanks: 4 
You started with the following: ( 0 ) = 0 but then comes following definition 1 * ( 0 ) = 1 = ( 0 ) * 1 If ( 0 ) = 0 won't the expression 1 * ( 0 ) be 0? 
December 5th, 2017, 07:02 AM  #3  
Banned Camp Joined: Aug 2012 Posts: 153 Thanks: 3  Quote:
The integer ( 0 ) does NOT possess the multiplicative property of zero The integer ( 0 ) does possess the multiplicative identity property of 1 Therefore n * ( 0) = n Thank you for your time Last edited by Conway51; December 5th, 2017 at 07:05 AM.  
December 5th, 2017, 08:17 AM  #4 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra 
So you have $$n = n \times (0) = n \times 0 = 0$$ Or is transitivity broken? 
December 5th, 2017, 10:01 AM  #5  
Banned Camp Joined: Aug 2012 Posts: 153 Thanks: 3  Quote:
NEVER does the equation ... n * 0 = 0 = n * ( 0 ) exist.... NEVER You will see only the equations n * 0 = 0 = 0 * n n * (0) = n = (0) * n Therefore the commutative property is preserved without change. Thank you very much for your time  
December 5th, 2017, 10:07 AM  #6  
Senior Member Joined: Sep 2015 From: USA Posts: 2,530 Thanks: 1390  Quote:
$n = n*(0) = n*(0) = 0$ contradiction either $(0) = 0$, with all the properties of $0$, or it doesn't. you can't just say $a=b$ but $a$ doesn't share some of $b$'s properties. do you have something other than equality in mind when you state $0 = (0)$ ? Last edited by romsek; December 5th, 2017 at 10:27 AM.  
December 5th, 2017, 10:13 AM  #7 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra  
December 5th, 2017, 10:21 AM  #8 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,674 Thanks: 2654 Math Focus: Mainly analysis and algebra 
You also claim the both $0$ and $(0)$ are the additive identity. Thus $$0=n + (n) = (0)$$ So either $0=(0)$ (meaning that they are the same element of the system) or addition is not well defined with every sum having two different answers, with no way of determining which is correct. 
December 5th, 2017, 11:08 AM  #9  
Banned Camp Joined: Aug 2012 Posts: 153 Thanks: 3  Quote:
any element added to the additive element is that element therefore... 0(the element) + (0)( the additive element) = 0 0 + (0) =/= (0) in the same way that 0(the element) + 0(the additive element) = 0 You will find NO where in the original post the equation.... 0 + (0) = (0) 0 = n + (n) = 0 Thank you for your time Last edited by Conway51; December 5th, 2017 at 11:16 AM.  
December 5th, 2017, 11:10 AM  #10  
Banned Camp Joined: Aug 2012 Posts: 153 Thanks: 3  Quote:
n = n * ( 0 ) = n * 0 = 0 ONLY the equations. n * (0) = n n * ( 0 ) = 0  

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