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March 31st, 2017, 01:26 PM   #1
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Fermat's last theorem

FERMAT’S LAST THEOREM
an + bn = cn
No three positive integers a, b and c satisfy the equation for value of n greater than 2

21power3 + 35power3 = 44power3
9261 + 42875 = 85184
Divide by 90
9261/90 42875/90 85184/90
equals
102.90 476.38 946.48
Round to
103 476 946
Times 90
103*90 476*90 946*90
Equals
9270 42840 85140
9261 42875 85184
Minus big from small ( stay within 1 to 45 )
9 + 35 = 44
44 = 44
Lourie 31 March 2017
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March 31st, 2017, 01:48 PM   #2
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Quote:
Originally Posted by Lourie View Post
FERMAT’S LAST THEOREM
an + bn = cn
No three positive integers a, b and c satisfy the equation for value of n greater than 2

21power3 + 35power3 = 44power3
9261 + 42875 = 85184
Divide by 90
9261/90 42875/90 85184/90
equals
102.90 476.38 946.48
Round to
103 476 946
Times 90
103*90 476*90 946*90
Equals
9270 42840 85140
9261 42875 85184
Minus big from small ( stay within 1 to 45 )
9 + 35 = 44
44 = 44
Lourie 31 March 2017
$\displaystyle 21^3 + 35^3 - 44^3 = -33048$
Try again.

-Dan

Last edited by topsquark; March 31st, 2017 at 01:50 PM.
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April 1st, 2017, 12:04 AM   #3
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Let us put it this way.

No three positive integers a,b, and c satisfy the equation of [ an+bn=cn ] for value of n bigger than 2.

meaning: an + bn can not equal cn according to the theorem?

Last edited by Lourie; April 1st, 2017 at 12:27 AM.
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April 1st, 2017, 12:37 AM   #4
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Quote:
Originally Posted by Lourie View Post
Let us put it this way.

No three positive integers a,b, and c satisfy the equation of [ an+bn=cn ] for value of n bigger than 2.

meaning: an + bn can not equal cn according to the theorem?
That is what Andrew Wiles et. al proved to be true, yes.
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