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 March 31st, 2017, 02:26 PM #1 Newbie   Joined: May 2016 From: Pretoria Posts: 7 Thanks: 0 Fermat's last theorem FERMATâ€™S LAST THEOREM an + bn = cn No three positive integers a, b and c satisfy the equation for value of n greater than 2 21power3 + 35power3 = 44power3 9261 + 42875 = 85184 Divide by 90 9261/90 42875/90 85184/90 equals 102.90 476.38 946.48 Round to 103 476 946 Times 90 103*90 476*90 946*90 Equals 9270 42840 85140 9261 42875 85184 Minus big from small ( stay within 1 to 45 ) 9 + 35 = 44 44 = 44 Lourie 31 March 2017
March 31st, 2017, 02:48 PM   #2
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Quote:
 Originally Posted by Lourie FERMATâ€™S LAST THEOREM an + bn = cn No three positive integers a, b and c satisfy the equation for value of n greater than 2 21power3 + 35power3 = 44power3 9261 + 42875 = 85184 Divide by 90 9261/90 42875/90 85184/90 equals 102.90 476.38 946.48 Round to 103 476 946 Times 90 103*90 476*90 946*90 Equals 9270 42840 85140 9261 42875 85184 Minus big from small ( stay within 1 to 45 ) 9 + 35 = 44 44 = 44 Lourie 31 March 2017
$\displaystyle 21^3 + 35^3 - 44^3 = -33048$
Try again.

-Dan

Last edited by topsquark; March 31st, 2017 at 02:50 PM.

 April 1st, 2017, 01:04 AM #3 Newbie   Joined: May 2016 From: Pretoria Posts: 7 Thanks: 0 Let us put it this way. No three positive integers a,b, and c satisfy the equation of [ an+bn=cn ] for value of n bigger than 2. meaning: an + bn can not equal cn according to the theorem? Last edited by Lourie; April 1st, 2017 at 01:27 AM.
April 1st, 2017, 01:37 AM   #4
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Quote:
 Originally Posted by Lourie Let us put it this way. No three positive integers a,b, and c satisfy the equation of [ an+bn=cn ] for value of n bigger than 2. meaning: an + bn can not equal cn according to the theorem?
That is what Andrew Wiles et. al proved to be true, yes.

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