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December 18th, 2016, 03:57 PM   #1
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Compute digit values

I don't know how to solve this problem. It says: "Let a,b,c,d digits (a>0), such that 0,abc = a/(b+c+d). Find all the possible values of a,b,c,d"

Any sugestion?
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December 18th, 2016, 04:25 PM   #2
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$0,abc$ ...

is that $\dfrac{a b c }{1000}$ ?

i.e. the comma is a decimal point?
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December 18th, 2016, 04:28 PM   #3
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Yes, it is. I have just write abc(b+c+d)=1000a but I can't solve nothing.

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December 18th, 2016, 04:53 PM   #4
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Quote:
Originally Posted by relativo94 View Post
Yes, it is. I have just write abc(b+c+d)=1000a but I can't solve nothing.

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I'm showing 1 solution.

hint a=1
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December 18th, 2016, 06:42 PM   #5
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Yeah, I get a=1, b=2, c=5, d=1

And with a=2 I get b=5, c=0, d=3

And there are no more solutions. Thanks for the hint
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December 18th, 2016, 07:28 PM   #6
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Quote:
Originally Posted by relativo94 View Post
Yeah, I get a=1, b=2, c=5, d=1

And with a=2 I get b=5, c=0, d=3

And there are no more solutions. Thanks for the hint
the 2nd one isn't a solution

you stated a,b,c,d > 0
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December 18th, 2016, 09:25 PM   #7
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It was stated that a > 0, not that a, b, c, d > 0.
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