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 December 18th, 2016, 02:57 PM #1 Newbie   Joined: Dec 2016 From: España Posts: 11 Thanks: 0 Math Focus: Logic Compute digit values I don't know how to solve this problem. It says: "Let a,b,c,d digits (a>0), such that 0,abc = a/(b+c+d). Find all the possible values of a,b,c,d" Any sugestion? Thanks!
 December 18th, 2016, 03:25 PM #2 Senior Member     Joined: Sep 2015 From: Southern California, USA Posts: 1,397 Thanks: 709 $0,abc$ ... is that $\dfrac{a b c }{1000}$ ? i.e. the comma is a decimal point?
 December 18th, 2016, 03:28 PM #3 Newbie   Joined: Dec 2016 From: España Posts: 11 Thanks: 0 Math Focus: Logic Yes, it is. I have just write abc(b+c+d)=1000a but I can't solve nothing. Thanks!
December 18th, 2016, 03:53 PM   #4
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Quote:
 Originally Posted by relativo94 Yes, it is. I have just write abc(b+c+d)=1000a but I can't solve nothing. Thanks!
I'm showing 1 solution.

hint a=1

 December 18th, 2016, 05:42 PM #5 Newbie   Joined: Dec 2016 From: España Posts: 11 Thanks: 0 Math Focus: Logic Yeah, I get a=1, b=2, c=5, d=1 And with a=2 I get b=5, c=0, d=3 And there are no more solutions. Thanks for the hint
December 18th, 2016, 06:28 PM   #6
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Quote:
 Originally Posted by relativo94 Yeah, I get a=1, b=2, c=5, d=1 And with a=2 I get b=5, c=0, d=3 And there are no more solutions. Thanks for the hint
the 2nd one isn't a solution

you stated a,b,c,d > 0

 December 18th, 2016, 08:25 PM #7 Global Moderator   Joined: Dec 2006 Posts: 17,908 Thanks: 1382 It was stated that a > 0, not that a, b, c, d > 0. Thanks from romsek

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