December 18th, 2016, 03:57 PM  #1 
Newbie Joined: Dec 2016 From: España Posts: 11 Thanks: 0 Math Focus: Logic  Compute digit values
I don't know how to solve this problem. It says: "Let a,b,c,d digits (a>0), such that 0,abc = a/(b+c+d). Find all the possible values of a,b,c,d" Any sugestion? Thanks! 
December 18th, 2016, 04:25 PM  #2 
Senior Member Joined: Sep 2015 From: CA Posts: 1,265 Thanks: 650 
$0,abc$ ... is that $\dfrac{a b c }{1000}$ ? i.e. the comma is a decimal point? 
December 18th, 2016, 04:28 PM  #3 
Newbie Joined: Dec 2016 From: España Posts: 11 Thanks: 0 Math Focus: Logic 
Yes, it is. I have just write abc(b+c+d)=1000a but I can't solve nothing. Thanks! 
December 18th, 2016, 04:53 PM  #4 
Senior Member Joined: Sep 2015 From: CA Posts: 1,265 Thanks: 650  
December 18th, 2016, 06:42 PM  #5 
Newbie Joined: Dec 2016 From: España Posts: 11 Thanks: 0 Math Focus: Logic 
Yeah, I get a=1, b=2, c=5, d=1 And with a=2 I get b=5, c=0, d=3 And there are no more solutions. Thanks for the hint 
December 18th, 2016, 07:28 PM  #6 
Senior Member Joined: Sep 2015 From: CA Posts: 1,265 Thanks: 650  
December 18th, 2016, 09:25 PM  #7 
Global Moderator Joined: Dec 2006 Posts: 17,524 Thanks: 1318 
It was stated that a > 0, not that a, b, c, d > 0.


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