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October 14th, 2016, 04:08 PM   #1
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Prime number theory

Prime number question:

Is the following prime number formula/theory viable: P = N – {2(N + 1)} – {3(2N + 1)} – {(6N-1)((6N-1) + (12N-1) + (18N-1) + (24N-1)+ …(6(∞)N-1))}
- {(6N+1)((6N-1) + (12N-1) + (18N-1) + (24N-1)+ …(6(∞)N-1))}
- {(6N+1)((6N+1) + (12N+1) + (18N+1) + (24N+1)+…(6(∞)N+1))} , where P is all primes, N is all natural whole numbers, and P≠ 0,1.?
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October 14th, 2016, 06:46 PM   #2
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Are you suggesting:
1) that this formula produces a prime for every natural number N; and
2) that the formula generates every prime number?

It sounds unlikely to me, but it's not my field. How many natural numbers have you checked your formula for?

Mobel is a number theorist on here who wishes to encourage creativity. I hope he has something useful to say on this.

Last edited by skipjack; October 16th, 2016 at 01:57 AM.
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October 14th, 2016, 07:14 PM   #3
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Quote:
Originally Posted by v8archie View Post

Mobel is a number theorist on here who wishes to encourage creativity. I hope he has something useful to say on this.
Nooo. We can't start doing this.

I think we should ask the mods to fix the block function.
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October 15th, 2016, 07:52 PM   #4
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I do believe (yes) that 1) this formula produces a prime for every natural number N; and
2) that the formula generates every prime number. But I will leave it up to the experts here to verify or discount the formula.
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October 16th, 2016, 04:29 AM   #5
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How many natural numbers have you tested to verify that they produce primes?

How many primes numbers have you tested to verify that they are produced by produce natural numbers?

What do you mean by $6(\infty)N-1$? The formula has three lines, can you explain how I generate a value for each line in order to combine them?

Last edited by v8archie; October 16th, 2016 at 04:35 AM.
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October 16th, 2016, 05:21 AM   #6
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6(∞)N -1 he means the big number that is a multiple of 6 minus 1.
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October 16th, 2016, 06:57 AM   #7
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this can be interesting because of the fact that every prime number is multiple of 6 minus or plus 1, but i think this formula is not well written and organized.
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October 17th, 2016, 05:49 AM   #8
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It is probably not well written and organized, I agree. With the tables I have concocted, I have simply discovered that not only do all primes exist within the parameters of
6N±1 (after the numbers 2 and 3), but that all non primes within 6N±1 are simply all of the multiples of all of those numbers within 6N±1 (without exception). My formula is an attempt (albeit lame, perhaps) of showing that all primes are elicited by removing the sets of those multiples of 2, and 3, and 6N±1. If mine is not correctly written, surely one with greater expertise than mine can accomplish it.
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