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July 30th, 2016, 03:49 AM  #11 
Senior Member Joined: Jun 2015 From: England Posts: 905 Thanks: 271 
What I was saying is that I think the set of all exponentiations $\displaystyle {q^r}$ : $\displaystyle q \in Q$ is countably infinite if $\displaystyle r \in Q$ but uncountable if $\displaystyle r \in R$ 
July 30th, 2016, 05:10 AM  #12  
Math Team Joined: Dec 2013 From: Colombia Posts: 7,634 Thanks: 2620 Math Focus: Mainly analysis and algebra  Quote:
In fact, an operator can be viewed as a singlevalued function $f(q_1,q_2,\ldots,q_n)$.  
July 30th, 2016, 12:33 PM  #13 
Senior Member Joined: May 2015 From: Arlington, VA Posts: 397 Thanks: 27 Math Focus: Number theory 
Thanks, both. I think I understand.


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cardinality, numbers, operations, rational 
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