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May 6th, 2016, 05:13 AM   #1
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Proof of Fermat's Last Theorem and Beal's Conjecture

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May 6th, 2016, 09:34 AM   #2
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Very interesting indeed.. But it says it is rejected and furthermore there is nothing to read..
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May 6th, 2016, 10:23 AM   #3
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You could read the paper. It's the three page PDF I expect.

But since it's a three page PDF purporting to solve not one, but two difficult problems and has been rejected twice, it seems highly unlikely that it is worth reading.
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May 6th, 2016, 11:30 AM   #4
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Why don"t you simply go through my work yourself and then acknowledge that this is the
proof.
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May 6th, 2016, 02:34 PM   #5
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Hold on wasn't Fermat's last theorem prove by some English chap like 2005 or something?

Last edited by skipjack; May 6th, 2016 at 09:38 PM.
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May 6th, 2016, 02:35 PM   #6
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I can't for the life of me remember his name, Andrew Wiles maybe?

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May 6th, 2016, 04:59 PM   #7
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Quote:
Originally Posted by MrAwojobi View Post
Why don"t you simply go through my work yourself and then acknowledge that this is the proof.
Because I'm more than 99% certain that it is not a proof and I have better things to do with my time than to read a paper that has been rejected twice. I'd be more interested in reading why they rejected it for the first time.
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May 6th, 2016, 11:48 PM   #8
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The so called maths professionals have the same attitude i.e. they are in denial that the solution to both similar problems is just as simple as the quote of the problems themselves. Andrew Wiles spent years on FLT, published a solution with errors before publishing a 100 page solution. 1 million dollars is placed on the solution of Beal"s conjecture. These are the reasons my correct simple solution is not taken seriously. On the reason given as to why my proof won't be published the reviewer said he had issues with equating indeterminate coefficients (to use his words) with fixed coefficients. His reason is nonsense
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May 7th, 2016, 01:41 AM   #9
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Mr.Awojobi or Mr.Otendute or whatever name you use.
You have tried posting your "proofs" in various fora,in various times,under various names.Only some of the flaws remain the same (ie.taking an equality as an identity).
I believe you are aware of this and only want to make a fuss,have people talk about you,or write etc.
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May 7th, 2016, 04:41 AM   #10
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An equation becomes an identity if the left hand side is equal to the right hand side for every value of the 2 variables written in red ink. Of course I have proved why these are not identities.
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