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October 19th, 2015, 01:02 PM   #1
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The 9 theory and The Infinity Theory

I was looking for ways to submit my theory to world , I didn't find any , so I chose Mathforum. Apply the 9 theory in your mind for every number. I Am Just 15


Only 10 Numbers exist In this universe ie 0 to 9 , while other numbers are just a form of nine or if represented in a single digit , they just 9

for example : 13 has the sum of its digits equal 4 and if we subtract 4 from 13 we get 9

87 has the sum of its digits equals 15 , if we subtract 15 from 87 we get 72 which is a multiple of 9 or in a single digit, 7+2 = 9.
It brings us the form: Original No - sum of its digits = multiple of nine (9n ) or in a single digit 9 , This is the 9 theory.
Now if we look at the difference between the original number and the sum of its digits , its entropy is increasing , eg: 54 has sum of digits 9 which is very small as compared to 16 which has 7 , the percentage is decreasing , so if we consider infinity , then a infinity the sum of digits will become negligibly smaller as compared to the original number (by graph ) then if we subtracted and use the form we used in the 9 theory , the resulting number we get is infinity only , and if 9 theory is true then infinity in a single digit is 9 and it can be represented in the form 9n
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October 19th, 2015, 01:32 PM   #2
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This is a form of casting out 9s, which in turn is a type of modular arithmetic.
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October 19th, 2015, 01:36 PM   #3
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I'd be uncomfortable with any theory about which numbers 'really exist' that assumes that numbers in base-10 are the only or most natural form of numbers.
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October 19th, 2015, 01:38 PM   #4
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Quote:
Originally Posted by Hedge View Post
I'd be uncomfortable with any theory about which numbers 'really exist' that assumes that numbers in base-10 are the only or most natural form of numbers.
Sure, the ontological claims are a bit strong here, but under the surface you're really only talking about working mod 9, and so it's not terribly surprising that you'd come up with 9 numbers.

Exercise: what happens if you do the same thing but replace base 10 with some other base?
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October 19th, 2015, 05:36 PM   #5
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Quote:
Originally Posted by CRGreathouse View Post
Exercise: what happens if you do the same thing but replace base 10 with some other base?
You mean taking the $(n-1)$-th numeral in base $B_n$? As I understood the trick is to use the representation of a natural number in some base $B$ like $N=a_nB^n+a_{n-1}B^{n-1}+\cdots+a_1B+a_0$ but writing it as $N=a_n([B-1]+1)^n+a_{n-1}([B-1]+1)^{n-1}+\cdots+a_1([B-1]+1)+a_0$ so that $a_n+\cdots+a_0\equiv N\pmod{B-1}$.
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October 22nd, 2015, 11:05 AM   #6
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Quote:
Originally Posted by CRGreathouse View Post
Exercise: what happens if you do the same thing but replace base 10 with some other base?
Interesting, thanks.
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