My Math Forum Onto and One-To-One Function

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 October 29th, 2011, 10:23 AM #1 Newbie   Joined: Oct 2011 Posts: 7 Thanks: 0 Onto and One-To-One Function Why is the following function (f(n) = n + 17), one-to-one, but not onto? The function should be able to take on values of (-inf,inf) in the codomain or range, correct?
 October 29th, 2011, 12:45 PM #2 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms Re: Onto and One-To-One Function I don't know. What's the domain? You'll get different answers depending on whether it's N -> N or R -> R or something else.
 October 29th, 2011, 03:35 PM #3 Newbie   Joined: Oct 2011 Posts: 7 Thanks: 0 Re: Onto and One-To-One Function N -> N
 October 29th, 2011, 03:51 PM #4 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms Re: Onto and One-To-One Function What value of n gives f(n) = 3?
 October 29th, 2011, 04:22 PM #5 Newbie   Joined: Oct 2011 Posts: 7 Thanks: 0 Re: Onto and One-To-One Function for the given fcn. (-14)... is that what you are asking? f(n) = n + 17; (-14) + 17 -> "3"
 October 29th, 2011, 04:25 PM #6 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms Re: Onto and One-To-One Function But -14 isn't in N.

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