October 29th, 2011, 01:25 AM  #1 
Member Joined: Sep 2011 Posts: 97 Thanks: 0  find a difference
Suppose a1, a2, a3, ..., a'n' is a sequence of n integers none of which is divisible by n. Show that at least one of the differences ai ? aj , 1 ? i; j ? n and i != j, must be divisible by n. 
October 29th, 2011, 08:34 AM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: find a difference
There are n1 nonzero remainders after dividing by n, but you have n numbers. Thus, two of the numbers must have the same remainder after dividing by n by the Pigeonhole Principle. This solves the problem  why?

October 29th, 2011, 11:33 AM  #3 
Member Joined: Sep 2011 Posts: 97 Thanks: 0  Re: find a difference
erm..ok but what is the at least one diff example?

October 29th, 2011, 01:45 PM  #4 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: find a difference
If n is 2, then by assumption both numbers are odd and hence their difference is even.

October 29th, 2011, 07:42 PM  #5 
Member Joined: Sep 2011 Posts: 97 Thanks: 0  Re: find a difference
yea, that's what i thougjht too haha initially i thought the n must be greater than all the sequence of integers in order to make them not divisble by n, haha 

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