April 10th, 2017, 06:35 PM  #121 
Senior Member Joined: Feb 2016 From: Australia Posts: 989 Thanks: 350 Math Focus: Yet to find out.  
April 12th, 2017, 07:30 AM  #122  
Senior Member Joined: Oct 2011 Posts: 122 Thanks: 1  Quote:
The answer to all questions is guaranteed.  
April 14th, 2017, 06:54 AM  #123 
Senior Member Joined: Oct 2011 Posts: 122 Thanks: 1  Are the axioms of mathematics wrong? WHY a raising of the digit by digit EQUALITY (in basis n) $\displaystyle 2^{nn}==(xn^2+2^{nn})(yn^2+1)$ mod $\displaystyle n^3$, where n is a prime number, n>2, x and y are digits y ≠ 0, [and x + 2y==0 mod n], in the (n1)th power, it turns into an INEQUALITY [and x + 4y==0 mod n]? 
April 19th, 2017, 07:43 AM  #124 
Senior Member Joined: Oct 2011 Posts: 122 Thanks: 1 
nn=n*n=n^2


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