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July 30th, 2014, 01:12 PM  #1 
Newbie Joined: Jul 2014 From: Near Canada Posts: 2 Thanks: 0  Kalphauer Theory Groundbreaking Theory? Yes or No? Need Help Completing Theory.
I live near the Canadian border. I spend some of my time looking at math formulas... I created this formula from scratch as I was looking into hertz as a decibel measurement. I am looking for fellow mathematicians to help me finish up this formula....this could be groundbreaking.. 1. I have taken the "Hz" measurement (Commonly used to calculate computer speeds, and started dividing and multiplying it by square roots of (Ghz) in which they are divisible. 2. I want your help in finishing my equation as my brain is shot from working on this formula for what seems like decades. 3. Your help is greatly appreciated. 4. Notice that I use some formulas FOUND as Greek numeric signs. ARE.YOU.READY? Here is the formula so far...notice the line breaks and arrows..thank you. Code: Kalphauer=.1Hz+(.1*.2*.3).4*.1Hz>.1<1Hzlint+(.01hz)= Talphaerry=({(1)(2)(3)+(.1)(.2)(.3)})Hz*Pi(Radius of core processor)*.1= neraguherhertz=(Kalphauer+Talphaerry)*3.14(of processor)/.4Hz~newline 1Hz((1.0e9 Ghz)=(60)R*P*M=360(Degrees))=(Degrees or Revolutions)newline newline Sn(rightarrow)Cos(rightarrow)sin(leftarrow)x?(rightarrow)deg(rightarrow)rev= (rightarrow)Hz=.1(Kal*Tal) newline newline (downarrow) or (rightarrow)(if)(Kal*Tal)=(.1)nablainfinity+nabla(Then)(.1(Hz))*(?Ghz*3.14)(rightarrow){.1}(if)(rightarrow){.2}(isgreater)(Than)(newroot)llint .3 newline newline Bin=0 or 1 newline stack{a.3 # b.2 # c+.1 # .1=a # .2=b # .3=a # (StackDown*.1Hz)} newline alignc matrix{a+.2 # a ## a # b.1} newline nroot{.1}{1}=arcsin(arccos(arctan(.1) ) )*.1a*.2b*.3c(If).1Hz=(Postive Number)nroot{.2}{.2}=(What Number) newline downarrow newline Kalphauer=(GREATEST or LEAST RESISTANT)(.1,.2,.3)count(rightarrow)resistance(rightarrow)(of)(hzghz construction) newline downarrow newline (i.e. DPS= Degrees Per Second, RPM= Revolutions Per Minute) newline newline .1 (rightarrow)=0.1 hertz = 1.0e10 gigahertz=0.1 hertz = 5.9(RPM)*(DPS=36) newline newline .2(rightarrow)=0.2 hertz = 2.0e10 gigahertz=0.2 hertz = 12 (RPM)*(DPS=71.9) newline newline .3 (rightarrow)=0.3 hertz = 3.0e10 gigahertz=0.3 hertz = 18 (RPM)*(DPS=108) newline newline Greastest or Least Resistant newline downarrow newline .?Hz*(1)=2.3%*nroot{4}{.1*.1}=(1st Step%ipsi) newline %ipsi*(.2*.001)*(1 div .02)=(2nd Step%xi) newline %xi div Last edited by skipjack; July 31st, 2014 at 04:00 PM. 

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completing, groundbreaking, kalphauer, theory 
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