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July 30th, 2014, 12:12 PM   #1
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Joined: Jul 2014
From: Near Canada

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Kalphauer Theory Groundbreaking Theory? Yes or No? Need Help Completing Theory.

I live near the Canadian border. I spend some of my time looking at math formulas... I created this formula from scratch as I was looking into hertz as a decibel measurement. I am looking for fellow mathematicians to help me finish up this formula....this could be groundbreaking..

1. I have taken the "Hz" measurement (Commonly used to calculate computer speeds, and started dividing and multiplying it by square roots of (Ghz) in which they are divisible.

2. I want your help in finishing my equation as my brain is shot from working on this formula for what seems like decades.

3. Your help is greatly appreciated.

4. Notice that I use some formulas FOUND as Greek numeric signs.

ARE.YOU.READY?





Here is the formula so far...notice the line breaks and arrows..thank you.

Code:
Kalphauer=.1Hz+(.1*.2*.3)-.4*.1Hz>.1<1Hzlint+(.01hz)=
Talphaerry=({(1)(2)(3)+(.1)(.2)(.3)})Hz*Pi(Radius of core processor)*.1=
neraguherhertz=(Kalphauer+Talphaerry)*3.14(of processor)/.4Hz~newline 
1Hz((1.0e-9 Ghz)=(60)R*P*M=360(Degrees))=(Degrees or Revolutions)newline 
newline
Sn(rightarrow)Cos(rightarrow)sin(leftarrow)x?(rightarrow)deg(rightarrow)rev= (rightarrow)Hz=.1(Kal*Tal)
newline
newline
(downarrow) or (rightarrow)(if)(Kal*Tal)=(.1)nabla-infinity+nabla(Then)(.1(Hz))*(?Ghz*3.14)(rightarrow){.1}(if)(rightarrow){.2}(isgreater)(Than)(newroot)llint .3   
newline
newline
Bin=0 or 1
newline
stack{a-.3 # b-.2 # c+.1 # .1=a # .2=b # .3=a # (StackDown*.1Hz)}
newline
alignc matrix{a+.2 # a ## a # b-.1}
newline
nroot{.1}{1}=arcsin(arccos(arctan(.1) ) )*.1a*.2b*.3c(If).1Hz=(Postive Number)nroot{.2}{.2}=(What Number)
newline
downarrow
newline Kalphauer=(GREATEST or LEAST RESISTANT)(.1,.2,.3)count(rightarrow)resistance(rightarrow)(of)(hz-ghz construction)
newline
downarrow
newline
(i.e. DPS= Degrees Per Second, RPM= Revolutions Per Minute)
newline
newline
.1 (rightarrow)=0.1 hertz = 1.0e-10 gigahertz=0.1 hertz = 5.9(RPM)*(DPS=36) 
newline
newline
.2(rightarrow)=0.2 hertz = 2.0e-10 gigahertz=0.2 hertz = 12 (RPM)*(DPS=71.9)
newline
newline
.3 (rightarrow)=0.3 hertz = 3.0e-10 gigahertz=0.3 hertz = 18 (RPM)*(DPS=108)
newline
newline
Greastest or Least Resistant
newline
downarrow
newline
.?Hz*(1)=2.3%*nroot{4}{.1*.1}=(1st Step%ipsi) 
newline
%ipsi*(.2*.001)*(1 div .02)=(2nd Step%xi)
newline
%xi div

Last edited by skipjack; July 31st, 2014 at 03:00 PM.
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