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September 8th, 2013, 09:19 PM  #1 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,483 Thanks: 950  Eddybob's problem of the week
Here's what Wolfram has if the 10^10 is replaced by a (10^20 = a^2): http://www.wolframalpha.com/input/?i=so ... %3D0+for+x YIKES 
September 9th, 2013, 03:20 PM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: Eddybob's problem of the week
Weird. Where do all the decimals come from?

September 9th, 2013, 08:06 PM  #3 
Senior Member Joined: Sep 2012 From: British Columbia, Canada Posts: 764 Thanks: 53  Re: Eddybob's problem of the week
Get the roots to 4 decimal places. I understand that the exact values are quite complicated.

September 9th, 2013, 09:15 PM  #4  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,483 Thanks: 950  Re: Eddybob's problem of the week Quote:
here: http://www.numberempire.com/equationsolver.php  
September 10th, 2013, 01:21 PM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,483 Thanks: 950  Re: Eddybob's problem of the week
x^4  (2*10^10  1) * x^3  x + 10^20 + 10^10  1 = 0 Let k = 10^10; then we have a quadratic: k^2 + (1  2x^3)k + x^4 + x^3  x  1 = 0 2k = 2x^3  1 + SQRT(4x^6  4x^4  8x^3 + 4x + 5) Ya, I know...so what!? 
September 10th, 2013, 04:23 PM  #6 
Senior Member Joined: Sep 2012 From: British Columbia, Canada Posts: 764 Thanks: 53  Re: Eddybob's problem of the week
You really know how to cheat, do you? 
September 10th, 2013, 07:53 PM  #7 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,483 Thanks: 950  Re: Eddybob's problem of the week
If you say so...


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