May 13th, 2013, 06:51 PM  #1 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,143 Thanks: 1003  Confusing...
Found this; I simply can't follow it... Anybody understand it? The three bears were sitting down to eat their porridge. It should have been a happy family occasion, but it soon became apparent to everyone that something was wrong. "Who's been eating my porridge?" they all cried, but the fact was, they'd eaten each others'! Mummy Bear had eaten half the amount that Daddy Bear would have had left in his bowl if only he had eaten from his bowl and noone else. Now, Baby Bear originally had 30 spoonfuls in his bowl, Mummy Bear had 60 and Daddy Bear had 90. Baby Bear had eaten half the amount that Mummy Bear would have had left in her bowl if only Daddy Bear had eaten from her bowl and had eaten one third of his actual total consumption. Daddy Bear had eaten the amount that Baby Bear would have had left if only Mummy Bear had eaten from Baby Bear's bowl and had eaten one third of her actual total consumption. How many spoonfuls of porridge had each bear eaten? 
May 15th, 2013, 10:42 AM  #2  
Senior Member Joined: Jul 2012 From: DFW Area Posts: 635 Thanks: 96 Math Focus: Electrical Engineering Applications  Re: Confusing...
Hi [color=#00BF00]Denis[/color], Here is what I get but it is lunch time and I did not get to check it: is the amount mommy bear eats. is the amount baby bear eats. is the amount daddy bear eats. Quote:
Quote:
Quote:
Quote:
Combining [1] and [3]: So: Plugging this value for into [3] and solving for the unknown gives: Finally, may be solved by plugging this value for into [2] and solving which gives:  
May 15th, 2013, 04:11 PM  #3 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,143 Thanks: 1003  Re: Confusing...
Gotcha! Thanks, JKS. I was assuming this meant each only ate from the other's bowls, not from their own: "... but the fact was, they'd eaten each others'! " 

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