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June 21st, 2019, 09:04 AM   #1
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Probability

"A lecturer teaches Digital Communication to 30 of her students. However she doesn't know if her student grasp her lecture. The students have to raise their hands if they dont grasp the lecture. She gives dice to a student and asks him to roll it. She does it with every student in the class. Following are the conditions 1)If 1 shows up, then the student honestly raises his/her hand if he/she did not understand the concept 2)If 2,3,5 show up then the student raises his/her hand irrespective of understanding the concept 3)If 4 or 6 shows up then student does not raise his/her hand. Let X~Bernoulli(q) where student raises his/her hand and Y~Bernoulli(p) where a student understands the concept. We can write q=Ap+B. Determine A and B."
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June 21st, 2019, 11:32 AM   #2
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Math Focus: सामान्य गणित
$\displaystyle q = \frac {-1}{6}p +\frac {2}{3}$

I got this
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June 22nd, 2019, 04:19 PM   #3
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Can you please elaborate your working please
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June 22nd, 2019, 04:45 PM   #4
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$q=P[X] = P[1]p + P[2,3,5] = \dfrac{p}{6} + \dfrac 1 2$

$A=\dfrac 1 6,~B=\dfrac 1 2$
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June 22nd, 2019, 11:21 PM   #5
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Let $\displaystyle p$ be the probability of understanding the concept.
$\displaystyle (1-p)$ = probablity of not undersranding the concept.

Since, 2, 3, 5 will always raise their hands. 4, 6 won't raise their hands. 1 will raise only if they dont understand.

Probability of hands being raised = $\displaystyle \frac {1}{2} + 0 + \frac {1}{6}(1-p) = \frac {-1}{6}p + \frac {2}{3 }$
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