May 11th, 2019, 02:50 PM  #1 
Newbie Joined: May 2019 From: Michigan Posts: 2 Thanks: 1  Simple question
Hello, I'm no mathematician, nor am I any good at math, but I somehow came across this odd set of equations that seem to always work out, with an exception. I was just messing around on my calculator, when the following equations seemed to work themselves out to me. IF a*b=c THEN c/sqrt b=x=a*sqrt b AND c/sqrt a=y=b*sqrt a EXCEPT IF a or b=0 I will post some examples below, as proof. DISCLAIMER: All numbers are rounded to the nearest thousandth. Ex 1. 95*42=3990 3990/sqrt 42=615.670=95*sqrt 42 3990/sqrt 92=409.365=42*sqrt 95 Ex 2. 0*5=0 0/sqrt 5=0=0*sqrt 5 2.236 is not equal to 0 0/sqrt 0=undefined, cannot devide by 0 5*sqrt 0=0 Ex 3. 3*9=27 27/sqrt 9=9=3*sqrt 9 27/sqrt 3=15.588=9*sqrt 3 If anyone can tell me if this has any significance, or what it has to do with, then please contact me. Thanks 
May 11th, 2019, 04:46 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,923 Thanks: 1518 
$a \cdot b =c$ note that $b=\sqrt{b} \cdot \sqrt{b}$ for $b >0$. Substitute the radical product for $b$ in the initial equation. $a \cdot \sqrt{b} \cdot \sqrt{b} = c$ now, divide both sides of the above equation by $\sqrt{b}$ ... 
May 11th, 2019, 05:52 PM  #3  
Newbie Joined: May 2019 From: Michigan Posts: 2 Thanks: 1  Quote:
I understand what you're trying to do, but my question was what it had to do with, like is it some part of calculus or trig, and also, what significance does it have? Thanks  
May 12th, 2019, 05:48 AM  #4 
Math Team Joined: Jul 2011 From: Texas Posts: 2,923 Thanks: 1518  

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