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May 11th, 2019, 02:50 PM   #1
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Simple question

Hello,

I'm no mathematician, nor am I any good at math, but I somehow came across this odd set of equations that seem to always work out, with an exception. I was just messing around on my calculator, when the following equations seemed to work themselves out to me.

IF a*b=c
THEN c/sqrt b=x=a*sqrt b
AND c/sqrt a=y=b*sqrt a
EXCEPT IF a or b=0

I will post some examples below, as proof.
DISCLAIMER: All numbers are rounded to the nearest thousandth.

Ex 1.
95*42=3990
3990/sqrt 42=615.670=95*sqrt 42
3990/sqrt 92=409.365=42*sqrt 95

Ex 2.
0*5=0
0/sqrt 5=0=0*sqrt 5
2.236 is not equal to 0
0/sqrt 0=undefined, cannot devide by 0
5*sqrt 0=0

Ex 3.
3*9=27
27/sqrt 9=9=3*sqrt 9
27/sqrt 3=15.588=9*sqrt 3

If anyone can tell me if this has any significance, or what it has to do with, then please contact me.

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May 11th, 2019, 04:46 PM   #2
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$a \cdot b =c$

note that $b=\sqrt{b} \cdot \sqrt{b}$ for $b >0$.
Substitute the radical product for $b$ in the initial equation.

$a \cdot \sqrt{b} \cdot \sqrt{b} = c$

now, divide both sides of the above equation by $\sqrt{b}$ ...
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May 11th, 2019, 05:52 PM   #3
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Quote:
Originally Posted by skeeter View Post
$a \cdot b =c$

note that $b=\sqrt{b} \cdot \sqrt{b}$ for $b >0$.
Substitute the radical product for $b$ in the initial equation.

$a \cdot \sqrt{b} \cdot \sqrt{b} = c$

now, divide both sides of the above equation by $\sqrt{b}$ ...
Hi Skeeter,

I understand what you're trying to do, but my question was what it had to do with, like is it some part of calculus or trig, and also, what significance does it have?

Thanks
Thanks from Rishan
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May 12th, 2019, 05:48 AM   #4
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Quote:
Originally Posted by codyjk727 View Post
Hi Skeeter,

I understand what you're trying to do, but my question was what it had to do with, like is it some part of calculus or trig, and also, what significance does it have?

Thanks
it's just algebra
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