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April 18th, 2019, 12:10 PM  #1 
Newbie Joined: Apr 2019 From: Pune Posts: 1 Thanks: 0  How to find the rotation vector by deriving the final vector with respect to the disp
My understanding of a rotation of a vector can be done by using a 2D rotation matrix as shown below, $R(\theta )=\begin{bmatrix}\cos \theta &\sin \theta \\\sin \theta &\cos \theta \\\end{bmatrix}$. This rotates column vectors by means of the following matrix multiplication, $\begin{bmatrix}x'\\y'\end{bmatrix} = \begin{bmatrix}\cos \theta &\sin \theta \\\sin \theta &\cos \theta \\\end{bmatrix}\begin{bmatrix}x\\y \end{bmatrix}$ For example, if you rotate the vector x=$\begin{bmatrix}1\\1 \end{bmatrix}$ by 45 degrees (clockwise), then the new vector is $\begin{bmatrix} \sqrt2 \\ 0 \end{bmatrix}$. **Other Method:** If I have only initial and final coordinates of the vectors [![enter image description here][1]][1] The initial vector is, V = $\begin{bmatrix}1\\1 \end{bmatrix}$ and the final vector is, v = V+d = $\begin{bmatrix} \sqrt2 \\ 0 \end{bmatrix}$. The displacement between these vectors is d = $\begin{bmatrix} \sqrt21 \\ 1 \end{bmatrix}$. Can I derive the final vector v with respect to displacement $\frac{\partial{v}}{\partial{d}}$ to get the rotation vector? [but returns a identity matrix] If so, does $\frac{\partial{v}}{\partial{d}} * d $ can be used to crosscheck? [1]: https://i.stack.imgur.com/hYDJn.png 
April 19th, 2019, 03:39 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 21,116 Thanks: 2331 
How would $\frac{\partial v}{\partial d}$ be defined?


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deriving, disp, final, find, respect, rotation, vector 
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