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| December 1st, 2018, 03:21 AM | #1 |
| Newbie Joined: Dec 2018 From: Italy Posts: 1 Thanks: 1 |  Greetings
Hello everybody! My name is Lorenzo and I am an Italian student of civil engineering. I love both math and English, so I thought that this forum will be the best! Have a nice afternoon! |
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| December 1st, 2018, 10:53 AM | #2 |
| Senior Member  Joined: Sep 2015 From: USA Posts: 2,430 Thanks: 1315 |
welcome!
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| December 6th, 2018, 03:20 AM | #3 |
| Newbie Joined: Dec 2018 From: UK Posts: 2 Thanks: 0 |
Hi Everyone, Glad to be here. Can any one help with the below. Can you help to derive a formula that can calculate b2, b3, b4 where T = a1(b1) + a2(b2) + a3(b3) + a4(b4) a1=a2=a3=a4=0.25 b1+b2+b3+b4=1 b1<b2<b3<b4 b1 = x1 T = y For example, one solution is b1=16%, b2=26%, b3=46% for Y = 2 and x1=12% 2 = 0.25(12%) + 0.25(16%) + 0.25(26%) + 0.25(46%) How to calculate b2, b3, b4 be when Y = 2 and x1 =14% 2 = 0.25(14%) + 0.25(?) + 0.25(?) + 0.25(?) |
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2Thanks
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