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January 1st, 2017, 01:53 PM  #1 
Newbie Joined: Jan 2017 From: lincoln Posts: 7 Thanks: 0  simultaneous equations
Help!!!!! A penalty cause states that a contractor will forfeit a certain sum of money for each day that they are late completing the contract. If they are 6 days late, they only receive Â£5000; if they are 14 days late, they receive Â£3000. A) Form a pair of simultaneous equations and find the amount of the daily forfeit using algebraic method. B) Calculate the value of the original contract using algebraic method. Help, please. Last edited by skipjack; January 1st, 2017 at 03:53 PM. 
January 1st, 2017, 02:03 PM  #2  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,726 Thanks: 651  Quote:
14  6 = 8 ; 5000  3000 = 2000 : 2000 / 8 = 250 per day Last edited by skipjack; January 1st, 2017 at 03:53 PM.  
January 1st, 2017, 02:05 PM  #3 
Newbie Joined: Jan 2017 From: lincoln Posts: 7 Thanks: 0  many thanks .....
That's brilliant. How do I put that in algebraic method?
Last edited by skipjack; January 1st, 2017 at 02:17 PM. 
January 1st, 2017, 02:08 PM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,726 Thanks: 651 
Not brilliant...no need for algebraic method. What grade are you in? 
January 1st, 2017, 02:17 PM  #5 
Newbie Joined: Jan 2017 From: lincoln Posts: 7 Thanks: 0 
it needs to be in algebraic

January 1st, 2017, 02:23 PM  #6 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,726 Thanks: 651 
Asked you what grade you're in...easier to help if we know that...

January 1st, 2017, 02:26 PM  #7 
Newbie Joined: Jan 2017 From: lincoln Posts: 7 Thanks: 0 
college

January 1st, 2017, 02:39 PM  #8 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,726 Thanks: 651 
x = days late (1st instance) y = days late (2nd instance) 6 and 14 in your case a = amount (1st instance) b = amount (2nd instance) 5000 and 3000 in your case Daily forfeit formula: (a  b) / (y  x) 

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equations, simultaneous 
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