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August 10th, 2016, 12:23 AM   #1
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Year 7 Math Problem (Puzzle)

CO + CO = NUT
In this sum each letter stand for a digit.

You must find a solution that works. Here are some attempts.
Think of reasons why the first and second attempts did not work. The third does work.
Can you find another solution?
1). 41 + 41 = 82 Wrong
2). 58 + 58 = 116 Wrong
3). 64 + 64 = 128 Correct
4). __ + __ = __

I have no idea what this means; please elaborate as much as possible about your answer.

Last edited by skipjack; August 10th, 2016 at 08:15 AM.
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August 10th, 2016, 01:03 AM   #2
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Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics
This is my guess:
1) Not enough digits as $\displaystyle N \neq 0$
2) Wrong because $\displaystyle N \neq U$.

So this might work, for example:
76 + 76 = 152
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