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January 7th, 2016, 02:28 AM  #11 
Newbie Joined: Jan 2016 From: Srilanka Posts: 7 Thanks: 0 
when c<a+b then c^n < [a+b]^n considering a,b,c are positive integers and n is a integer. I remind you Fermat also select same numbers. Because when a,b,c are not integers and n is not a not a integer, then It may c^n > [a+b]^n, That is why Fermat selected integers only. Then there is a indication come, Fermat also had followed my method.
Last edited by gishan; January 7th, 2016 at 02:36 AM. 
January 7th, 2016, 02:37 AM  #12 
Global Moderator Joined: Dec 2006 Posts: 19,505 Thanks: 1740 
That also holds for positive a, b and c that are not all integers, so you are not relying on a, b and c all being integers.

January 7th, 2016, 03:58 PM  #13  
Newbie Joined: Jan 2016 From: Srilanka Posts: 7 Thanks: 0  Quote:
 
January 7th, 2016, 07:11 PM  #14 
Global Moderator Joined: Dec 2006 Posts: 19,505 Thanks: 1740 
As Fermat is no longer alive, he doesn't know anything now, and we can't ever know for certain what ideas he had but left undisclosed. A purported proof that contains a mathematically invalid step is, by definition, not a valid proof, and the same applies to any currently secret purported proof that uses that same invalid step.


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