My Math Forum  

Go Back   My Math Forum > Math Forums > Math

Math General Math Forum - For general math related discussion and news


Thanks Tree6Thanks
Reply
 
LinkBack Thread Tools Display Modes
November 25th, 2014, 07:44 PM   #21
Senior Member
 
MarkFL's Avatar
 
Joined: Jul 2010
From: St. Augustine, FL., U.S.A.'s oldest city

Posts: 12,211
Thanks: 521

Math Focus: Calculus/ODEs
Quote:
Originally Posted by Math Message Board tutor View Post
You have rocks in your head, and your a psychotic liar. You need those
rocks kicked out of your head. I told you to stop posting on this thread, you punk.
You're to do what I tell you to do, you persistent troll. Get off the thread!
Please post civilly and without painting violent pictures.

You cannot dictate who posts where, no matter how much you may dislike someone. I would advise you to revise your list of ignored users if you do not like what a particular person has to say.

But, you cannot be calling people names and telling them they need for their heads to be kicked. Be advised that this will not be tolerated.
MarkFL is offline  
 
November 25th, 2014, 07:48 PM   #22
Banned Camp
 
Joined: Jun 2014
From: Earth

Posts: 945
Thanks: 191

I'm advising you, MarkFL and all of the moderators, *take care of business*
and ban him now and delete his posts off of this thread, because they're inappropriate.
How many times must I send PMs to your moderators for his repeat harassment!?
YOU take care of business on YOUR end now.

Last edited by skipjack; November 27th, 2014 at 11:28 AM.
Math Message Board tutor is offline  
November 25th, 2014, 07:53 PM   #23
Senior Member
 
MarkFL's Avatar
 
Joined: Jul 2010
From: St. Augustine, FL., U.S.A.'s oldest city

Posts: 12,211
Thanks: 521

Math Focus: Calculus/ODEs
Quote:
Originally Posted by Math Message Board tutor View Post
I'm advising you, MarkFL and all of the moderators, *take care of business*
and ban him now and delete his posts off of this thread, because they're inappropriate.
How many times must I send PM's to your moderators for his repeat harassment!?
YOU take care of business on YOUR end now.
We are taking care of business, thank you very much.

You are abusing the "Report Post" feature, when it is in fact you who are posting inappropriately. You apparently do not take it well when someone disagrees with you, and then you call for their posts to be deleted.

We are not going to delete posts because you don't like that someone disagreed with you.

So, when someone disagrees with you, refute them civilly, or ignore them, but do not call them names, or otherwise become aggressive.
Thanks from greg1313 and agentredlum

Last edited by skipjack; November 27th, 2014 at 11:29 AM.
MarkFL is offline  
November 25th, 2014, 08:00 PM   #24
Banned Camp
 
Joined: Jun 2014
From: Earth

Posts: 945
Thanks: 191

Quote:
Originally Posted by jks View Post
$\displaystyle \large \frac{8}{\left(\sqrt{\sqrt{8+8}}\right)!} \ !$

$\displaystyle \large \sqrt{8 \times \left(\sqrt{\sqrt{8+8}}\right)!} \quad !$

I think I can guess why the number of factorials is limited to 2.
These two expressions don't count, because the factorial signs next to each parenthetical expression
can be removed and the expression still equals 24. In other words,
they are not necessary. Only the outermost factorial sign on each one to make them four factorial, respectively, are required.
Math Message Board tutor is offline  
November 25th, 2014, 08:01 PM   #25
Senior Member
 
MarkFL's Avatar
 
Joined: Jul 2010
From: St. Augustine, FL., U.S.A.'s oldest city

Posts: 12,211
Thanks: 521

Math Focus: Calculus/ODEs
$\displaystyle \frac{8!!}{8+8}=24$
MarkFL is offline  
November 25th, 2014, 08:12 PM   #26
Banned Camp
 
Joined: Jun 2014
From: Earth

Posts: 945
Thanks: 191

Quote:
Originally Posted by MarkFL View Post
$\displaystyle \frac{8!!}{8+8}=24$
The double factorial one is valid.

Then there are more than the five I referred to.

Last edited by Math Message Board tutor; November 25th, 2014 at 08:15 PM.
Math Message Board tutor is offline  
November 26th, 2014, 07:39 PM   #27
jks
Senior Member
 
jks's Avatar
 
Joined: Jul 2012
From: DFW Area

Posts: 635
Thanks: 96

Math Focus: Electrical Engineering Applications
$\displaystyle \large \sqrt{\sqrt{8 \times 8}+8} \quad !$
jks is offline  
November 26th, 2014, 07:53 PM   #28
Banned Camp
 
Joined: Jun 2014
From: Earth

Posts: 945
Thanks: 191

Quote:
Originally Posted by jks View Post
$\displaystyle \large \sqrt{\sqrt{8 \times 8}+8} \quad !$
Yes.
Math Message Board tutor is offline  
November 26th, 2014, 08:02 PM   #29
Senior Member
 
Joined: Jan 2014
From: The backwoods of Northern Ontario

Posts: 390
Thanks: 70

Quote:
The double factorial one is valid.
I don't understand how it can be valid

8! = 40320
Thus 8!!= 40320!

This woud be a very large number. Divide it by 16 and you surely don't get 24.
Timios is offline  
November 26th, 2014, 08:50 PM   #30
jks
Senior Member
 
jks's Avatar
 
Joined: Jul 2012
From: DFW Area

Posts: 635
Thanks: 96

Math Focus: Electrical Engineering Applications
$\displaystyle 8!! \ = \ 8 \times 6 \times 4 \times 2$

Look here.
Thanks from MarkFL
jks is offline  
Reply

  My Math Forum > Math Forums > Math

Tags
challenge, make, puzzle



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
can someone make an example against? PerAA Number Theory 6 September 22nd, 2013 08:18 PM
Trying to make a challenge mathmaniac Number Theory 1 May 14th, 2013 08:00 AM
What would you like me to try to make? NeuroFuzzy Math Software 1 December 25th, 2010 07:55 AM
I want o make sure im right. katfisher1208 Algebra 1 May 1st, 2010 10:59 AM
one more limit(to make sure) mathman2 Calculus 1 October 22nd, 2009 05:20 PM





Copyright © 2019 My Math Forum. All rights reserved.