My Math Forum > Math 3 8's to make 24 -- my challenge puzzle

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 November 25th, 2014, 04:27 PM #11 Senior Member   Joined: Jan 2014 From: The backwoods of Northern Ontario Posts: 390 Thanks: 70 Okay Board Tutor, you gave it away! $\displaystyle (8-\sqrt{8+8})!$
 November 25th, 2014, 04:36 PM #12 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,656 Thanks: 2634 Math Focus: Mainly analysis and algebra $$\sqrt{8\sqrt{\sqrt{8+8}}}!$$
November 25th, 2014, 04:37 PM   #13
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Quote:
 Originally Posted by v8archie No it isn't. Just because your pedantry has backfired doesn't mean that others aren't justified in their comments.
Yes, the comment is null and void. My pedantry hasn't backfired, because
I explained about the modification. If you don't want to use your brain and accept it,
then you can *leave* the forum to others with sense of acknowledging modifications.
Now don't bother posting anymore to the contrary, else you're just being a troll. Clear!?

Edit: I'll not count any of your alleged solutions until I get a retraction from your post.
It's currently post # 10.

Last edited by Math Message Board tutor; November 25th, 2014 at 04:44 PM.

November 25th, 2014, 04:53 PM   #14
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Your "explanation" came after the suggestion that you had erred. It is clearly a bad reaction to another user working to the letter of your own rules.

You seem to be under the misguided impression that everybody in these forums has to post according to your rules. This is patently not the case. You are no better than anyone else on these forums, whatever you may think or your posting style imply. I am under no compulsion to either acknowledge your modifications, your instructions or to leave the forums.
Quote:
 Originally Posted by Math Message Board tutor Edit: I'll not count any of your alleged solutions until I get a retraction from your post.
I'm not interested in the slightest in whether you acknowledge any post of mine. Don't forget to pick up those toys before you go to bed.

November 25th, 2014, 05:37 PM   #15
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Quote:
 Originally Posted by v8archie You seem to be under the misguided impression that everybody in these forums has to post according to your rules. I'm under no misguided impression. And, starting with you, you're going to do what I state with you being civil because you have repeatedly violated it. And you can experience a ban for doing so. This is patently not the case. You are no better than anyone else on these forums, Of course I am better than anyone on this forum. You're such a person. You continue to prove it by being a troll and instigating, each time adding support for your ban. So you're also a liar. whatever you may think or your posting style imply. I am under no compulsion to either acknowledge your modifications, your instructions or to leave the forums. Wrong, I order you to acknowledge the modification. But because you refuse to be civil, just stop posting on this thread. I'm not interested in the slightest in whether you acknowledge any post of mine. Don't forget to pick up those toys before you go to bed.
If you had integrity, then you would be interested, but you don't.

Take your last comment, of which it is particularly false and immature, and turn it back upon yourself.
Don't post anymore on this thread. You were reported.
And you're being reported again for being uncivil.

 November 25th, 2014, 06:52 PM #16 Senior Member     Joined: Jul 2012 From: DFW Area Posts: 635 Thanks: 96 Math Focus: Electrical Engineering Applications $\displaystyle \large \frac{8}{\sqrt{\sqrt{8+8}}} \ !$
November 25th, 2014, 07:00 PM   #17
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Quote:
 Originally Posted by jks $\displaystyle \large \frac{8}{\sqrt{\sqrt{8+8}}} \ !$
Yes.

 November 25th, 2014, 07:12 PM #18 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,656 Thanks: 2634 Math Focus: Mainly analysis and algebra Perhaps, had I been uncivil here, I would receive a ban. But since I haven't, I consider it unlikely. Perhaps I'll get a medal for resisting the urge to become uncivil in the face of your unnecessarily aggressive posts. I'm certainly not going to respond to commands from you. Mind you, were I to stop posting here, this tired excuse for a conversation would mercifully draw to a close. Have we only got three of these so far? What a shame! PS: I don't see any connection between integrity and worrying myself over what you say.
 November 25th, 2014, 07:27 PM #19 Senior Member     Joined: Jul 2012 From: DFW Area Posts: 635 Thanks: 96 Math Focus: Electrical Engineering Applications $\displaystyle \large \frac{8}{\left(\sqrt{\sqrt{8+8}}\right)!} \ !$ $\displaystyle \large \sqrt{8 \times \left(\sqrt{\sqrt{8+8}}\right)!} \quad !$ I think I can guess why the number of factorials is limited to 2.
November 25th, 2014, 07:34 PM   #20
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Quote:
 Originally Posted by v8archie Perhaps, had I been uncivil here, I would receive a ban. But since I haven't, I consider it unlikely. Perhaps I'll get a medal for resisting the urge to become uncivil in the face of your unnecessarily aggressive posts. I'm certainly not going to respond to commands from you. Mind you, were I to stop posting here, this tired excuse for a conversation would mercifully draw to a close. Have we only got three of these so far? What a shame! PS: I don't see any connection between integrity and worrying myself over what you say.
rocks no longer in your head. I told you to stop posting on this thread, you punk.
You're to do what I tell you to do, you persistent troll. Get off the thread!

edit

Last edited by Math Message Board tutor; November 25th, 2014 at 07:50 PM.

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