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July 4th, 2014, 02:50 AM  #1 
Member Joined: Jun 2014 From: Brighton Posts: 49 Thanks: 2  A problem on men and work
Help required to solve algebra 2 homework A can do a piece of work in 5 days, but with the help of B,A can do it in 3 days. In how much time B alone can complete the same piece of work ? Thanks 
July 4th, 2014, 05:36 PM  #2  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Hello, burgess! Quote:
$A$ does the job in 5 days. $\quad$In one day, $A$ does $\tfrac{1}{5}$ of the job. $B$ does the job in $b$ days. $\quad$In one day, $B$ does $\tfrac{1}{b}$ of the job. In one day, working together, they can do $\tfrac{1}{5} + \tfrac{1}{b}$ of the job. We are told that, working together, they can do the job in 3 days. That is, in one day, working together, they can do $\tfrac{1}{3}$ of the job. There is our equation! . . . $\dfrac{1}{5} + \dfrac{1}{b} \;=\;\dfrac{1}{3}$ Solve for $b$.  

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