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June 25th, 2014, 11:08 AM   #1
Math Team
Joined: Oct 2011
From: Ottawa Ontario, Canada

Posts: 14,597
Thanks: 1038

One for long_quach

A's age is twice what B's age was when C was half present age.

In 30 years from now, B'a age will be the sum of A's and C's present ages.

When A's age was B's present age, C's age was 1/3 of present age.

Long_quach has been appointed (due to his love for these) to solve
for the above 3 ages. Good luck from us all
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