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June 25th, 2014, 11:08 AM  #1 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,299 Thanks: 1023  One for long_quach
A's age is twice what B's age was when C was half present age. In 30 years from now, B'a age will be the sum of A's and C's present ages. When A's age was B's present age, C's age was 1/3 of present age. Long_quach has been appointed (due to his love for these) to solve for the above 3 ages. Good luck from us all 