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November 4th, 2019, 06:56 AM  #1 
Member Joined: Feb 2018 From: Iran Posts: 57 Thanks: 3  Trignometry
In a triangle ABC A=90 degree And (bc)/(b+c)= 1/sqrt(3) Find angle B?? 
November 4th, 2019, 07:43 AM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 3,093 Thanks: 1675 
$\dfrac{bc}{b+c} = \dfrac{1}{\sqrt{3}} \implies \dfrac{b}{c} = 2+\sqrt{3}$ $B = \arctan\left(\dfrac{b}{c}\right)$ 

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