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November 4th, 2019, 06:56 AM   #1
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Unhappy Trignometry

In a triangle ABC A=90 degree
And (b-c)/(b+c)= 1/sqrt(3)
Find angle B??
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November 4th, 2019, 07:43 AM   #2
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$\dfrac{b-c}{b+c} = \dfrac{1}{\sqrt{3}} \implies \dfrac{b}{c} = 2+\sqrt{3}$

$B = \arctan\left(\dfrac{b}{c}\right)$
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