My Math Forum > Math bizzare continuation Zn

 Math General Math Forum - For general math related discussion and news

 August 6th, 2019, 03:51 AM #1 Newbie   Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 bizzare continuation Zn Hello everyone, Here is a bizzare continuation Zn = (10 + 325 * n) ^ n / (3 * 10 * 10 ^ n * n ^ n) What bizzare is that I can give you Z1 Z2 Z 3 Z4 .... Z100000 but you can not find the general term of this sequel. My question is why? 1 ,36,Z,38346,1246285..... find Z and Zn?
 August 6th, 2019, 01:49 PM #2 Global Moderator   Joined: May 2007 Posts: 6,806 Thanks: 716 The expression for Zn is the general term. What are you looking for?
 August 6th, 2019, 01:54 PM #3 Newbie   Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 If I give you Z1 Z2 Z3 ... Z10000 and I ask you to find Zn or Z2 you'll tell me I'm inventing numbers.
August 6th, 2019, 02:40 PM   #4
Math Team

Joined: May 2013
From: The Astral plane

Posts: 2,257
Thanks: 927

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
 Originally Posted by Zouha10 If I give you Z1 Z2 Z3 ... Z10000 and I ask you to find Zn or Z2 you'll tell me I'm inventing numbers.
Ummmm...
$\displaystyle Z_n = \dfrac{(10 + 325n) ^n}{ 30 \cdot 10 ^ n \cdot n ^ n}$

and
$\displaystyle Z_2 = \dfrac{(10 + 325 \cdot 2) ^2}{ 30 \cdot 10 ^2 \cdot 2^2} = 36.3$
if I did that correctly.

Why would we be having to "make up numbers?" You've given the formula for all n. Just use it.

-Dan

 August 7th, 2019, 03:33 AM #5 Newbie   Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 But what if I give you the value of z1 z2? z4 z5 .. Z10000 you can not find Z3 and the general term Zn Look here he can not find z3 and zn. And they say it's not mathematical. https://forums.futura-sciences.com/m...trouver-z.html 1 ,36,Z,38346,1246285..... find Z and Zn? Last edited by Zouha10; August 7th, 2019 at 03:37 AM.
August 7th, 2019, 06:12 AM   #6
Math Team

Joined: May 2013
From: The Astral plane

Posts: 2,257
Thanks: 927

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
 Originally Posted by Zouha10 But what if I give you the value of z1 z2? z4 z5 .. Z10000 you can not find Z3 and the general term Zn Look here he can not find z3 and zn. And they say it's not mathematical. https://forums.futura-sciences.com/m...trouver-z.html 1 ,36,Z,38346,1246285..... find Z and Zn?
I think that we have a translation problem. I don't think we are trying to solve the same problem. The way I see it is that you gave a formula for all n so there is no problem finding Z_n for any n.

If that isn't the solution then I'm not understanding the problem.

-Dan

 August 7th, 2019, 08:32 AM #7 Newbie   Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 Yes i use translation google. For example 1 2 3 4 .... It's easy to say that Un = n and I gave that 1 2 3 4 But for Zn even if I give you Z1 Z2 Z3 Z4 Z5 .... Z1000 impossible to find Zn The question and why is it difficult to find Zn? Last edited by Zouha10; August 7th, 2019 at 08:40 AM.
August 7th, 2019, 09:35 AM   #8
Math Team

Joined: May 2013
From: The Astral plane

Posts: 2,257
Thanks: 927

Math Focus: Wibbly wobbly timey-wimey stuff.
Quote:
 Originally Posted by Zouha10 Yes i use translation google. For example 1 2 3 4 .... It's easy to say that Un = n and I gave that 1 2 3 4 But for Zn even if I give you Z1 Z2 Z3 Z4 Z5 .... Z1000 impossible to find Zn The question and why is it difficult to find Zn?
That's the whole problem I have with your question! You gave us an expression for Z_n! You defined
$\displaystyle Z_n = \dfrac{(10 + 325n)^n}{3 \cdot 10 \cdot 10^n \cdot n^n}$

That is your formula for Z_n that you are saying is so hard to find! You gave the answer to your own question.

-Dan

 August 7th, 2019, 09:46 AM #9 Newbie   Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 Yes but if I want to give z1 z2 z3 z4 ..... Z99999 And I see asks to find Zn the answer is impossible to find Zn.
 August 7th, 2019, 02:58 PM #10 Member     Joined: Oct 2018 From: USA Posts: 88 Thanks: 61 Math Focus: Algebraic Geometry I BELIEVE Zouha is trying to ask that if you assume you don't know the general form, is it possible to derive the general form $Z_n$ from some given $z_n$'s Thanks from topsquark and DarnItJimImAnEngineer

 Tags bizzare, continuation

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post bluebird01 Complex Analysis 1 September 18th, 2016 07:11 AM esavaleo8 Complex Analysis 0 August 22nd, 2016 11:34 AM neelmodi Complex Analysis 2 August 21st, 2014 03:52 PM honzik Complex Analysis 6 May 11th, 2012 03:33 PM davedave Complex Analysis 3 January 16th, 2010 04:33 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top