August 6th, 2019, 04:51 AM  #1 
Newbie Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0  bizzare continuation Zn
Hello everyone, Here is a bizzare continuation Zn = (10 + 325 * n) ^ n / (3 * 10 * 10 ^ n * n ^ n) What bizzare is that I can give you Z1 Z2 Z 3 Z4 .... Z100000 but you can not find the general term of this sequel. My question is why? 1 ,36,Z,38346,1246285..... find Z and Zn? 
August 6th, 2019, 02:49 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,855 Thanks: 744 
The expression for Zn is the general term. What are you looking for?

August 6th, 2019, 02:54 PM  #3 
Newbie Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 
If I give you Z1 Z2 Z3 ... Z10000 and I ask you to find Zn or Z2 you'll tell me I'm inventing numbers.

August 6th, 2019, 03:40 PM  #4  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,344 Thanks: 985 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle Z_n = \dfrac{(10 + 325n) ^n}{ 30 \cdot 10 ^ n \cdot n ^ n}$ and $\displaystyle Z_2 = \dfrac{(10 + 325 \cdot 2) ^2}{ 30 \cdot 10 ^2 \cdot 2^2} = 36.3$ if I did that correctly. Why would we be having to "make up numbers?" You've given the formula for all n. Just use it. Dan  
August 7th, 2019, 04:33 AM  #5 
Newbie Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 
But what if I give you the value of z1 z2? z4 z5 .. Z10000 you can not find Z3 and the general term Zn Look here he can not find z3 and zn. And they say it's not mathematical. https://forums.futurasciences.com/m...trouverz.html 1 ,36,Z,38346,1246285..... find Z and Zn? Last edited by Zouha10; August 7th, 2019 at 04:37 AM. 
August 7th, 2019, 07:12 AM  #6  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,344 Thanks: 985 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
If that isn't the solution then I'm not understanding the problem. Dan  
August 7th, 2019, 09:32 AM  #7 
Newbie Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 
Yes i use translation google. For example 1 2 3 4 .... It's easy to say that Un = n and I gave that 1 2 3 4 But for Zn even if I give you Z1 Z2 Z3 Z4 Z5 .... Z1000 impossible to find Zn The question and why is it difficult to find Zn? Last edited by Zouha10; August 7th, 2019 at 09:40 AM. 
August 7th, 2019, 10:35 AM  #8  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,344 Thanks: 985 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
$\displaystyle Z_n = \dfrac{(10 + 325n)^n}{3 \cdot 10 \cdot 10^n \cdot n^n}$ That is your formula for Z_n that you are saying is so hard to find! You gave the answer to your own question. Dan  
August 7th, 2019, 10:46 AM  #9 
Newbie Joined: Jun 2019 From: Casablanca https://extrazlove.blogspot.com/ extrazlove https://extrazlove.blogspot.com Posts: 19 Thanks: 0 
Yes but if I want to give z1 z2 z3 z4 ..... Z99999 And I see asks to find Zn the answer is impossible to find Zn. 
August 7th, 2019, 03:58 PM  #10 
Senior Member Joined: Oct 2018 From: USA Posts: 102 Thanks: 77 Math Focus: Algebraic Geometry 
I BELIEVE Zouha is trying to ask that if you assume you don't know the general form, is it possible to derive the general form $Z_n$ from some given $z_n$'s


Tags 
bizzare, continuation 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Find an analytic continuation  bluebird01  Complex Analysis  1  September 18th, 2016 08:11 AM 
Analytic Continuation  esavaleo8  Complex Analysis  0  August 22nd, 2016 12:34 PM 
Understanding Analytic Continuation  neelmodi  Complex Analysis  2  August 21st, 2014 04:52 PM 
Analytic continuation  honzik  Complex Analysis  6  May 11th, 2012 04:33 PM 
a problem on analytic continuation  davedave  Complex Analysis  3  January 16th, 2010 05:33 PM 