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August 6th, 2019, 04:51 AM   #1
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bizzare continuation Zn

Hello everyone,

Here is a bizzare continuation Zn = (10 + 325 * n) ^ n / (3 * 10 * 10 ^ n * n ^ n)

What bizzare is that I can give you Z1 Z2 Z 3 Z4 .... Z100000 but you can not find the general term of this sequel.


My question is why?

1 ,36,Z,38346,1246285..... find Z and Zn?
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August 6th, 2019, 02:49 PM   #2
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The expression for Zn is the general term. What are you looking for?
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August 6th, 2019, 02:54 PM   #3
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If I give you Z1 Z2 Z3 ... Z10000 and I ask you to find Zn or Z2 you'll tell me I'm inventing numbers.
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August 6th, 2019, 03:40 PM   #4
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Originally Posted by Zouha10 View Post
If I give you Z1 Z2 Z3 ... Z10000 and I ask you to find Zn or Z2 you'll tell me I'm inventing numbers.
Ummmm...
$\displaystyle Z_n = \dfrac{(10 + 325n) ^n}{ 30 \cdot 10 ^ n \cdot n ^ n}$

and
$\displaystyle Z_2 = \dfrac{(10 + 325 \cdot 2) ^2}{ 30 \cdot 10 ^2 \cdot 2^2} = 36.3$
if I did that correctly.

Why would we be having to "make up numbers?" You've given the formula for all n. Just use it.

-Dan
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August 7th, 2019, 04:33 AM   #5
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But what if I give you the value of z1 z2? z4 z5 .. Z10000 you can not find Z3 and the general term Zn

Look here he can not find z3 and zn.
And they say it's not mathematical.

https://forums.futura-sciences.com/m...trouver-z.html

1 ,36,Z,38346,1246285..... find Z and Zn?

Last edited by Zouha10; August 7th, 2019 at 04:37 AM.
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August 7th, 2019, 07:12 AM   #6
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Quote:
Originally Posted by Zouha10 View Post
But what if I give you the value of z1 z2? z4 z5 .. Z10000 you can not find Z3 and the general term Zn

Look here he can not find z3 and zn.
And they say it's not mathematical.

https://forums.futura-sciences.com/m...trouver-z.html

1 ,36,Z,38346,1246285..... find Z and Zn?
I think that we have a translation problem. I don't think we are trying to solve the same problem. The way I see it is that you gave a formula for all n so there is no problem finding Z_n for any n.

If that isn't the solution then I'm not understanding the problem.

-Dan
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August 7th, 2019, 09:32 AM   #7
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Yes i use translation google.

For example 1 2 3 4 ....
It's easy to say that Un = n and I gave that 1 2 3 4
But for Zn even if I give you Z1 Z2 Z3 Z4 Z5 .... Z1000 impossible to find Zn

The question and why is it difficult to find Zn?

Last edited by Zouha10; August 7th, 2019 at 09:40 AM.
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August 7th, 2019, 10:35 AM   #8
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Originally Posted by Zouha10 View Post
Yes i use translation google.

For example 1 2 3 4 ....
It's easy to say that Un = n and I gave that 1 2 3 4
But for Zn even if I give you Z1 Z2 Z3 Z4 Z5 .... Z1000 impossible to find Zn

The question and why is it difficult to find Zn?
That's the whole problem I have with your question! You gave us an expression for Z_n! You defined
$\displaystyle Z_n = \dfrac{(10 + 325n)^n}{3 \cdot 10 \cdot 10^n \cdot n^n}$

That is your formula for Z_n that you are saying is so hard to find! You gave the answer to your own question.

-Dan
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August 7th, 2019, 10:46 AM   #9
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Yes but if I want to give z1 z2 z3 z4 ..... Z99999
And I see asks to find Zn the answer is impossible to find Zn.
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August 7th, 2019, 03:58 PM   #10
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I BELIEVE Zouha is trying to ask that if you assume you don't know the general form, is it possible to derive the general form $Z_n$ from some given $z_n$'s
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