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February 12th, 2019, 09:25 AM  #1 
Member Joined: Feb 2018 From: England Posts: 61 Thanks: 0  Formula
Hi All, Is there a formula to convert 1.21x10^8 1s1 to 1.22x10^8kg (3 s.f)? Thanks for any help. 
February 12th, 2019, 10:01 AM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 2,404 Thanks: 1306 
there has to be more to this than you've written.... why should you be able to convert $Hz$ to $kg \cdot ft^2$ ? 
February 12th, 2019, 11:48 PM  #3 
Member Joined: Feb 2018 From: England Posts: 61 Thanks: 0 
Hi Romsek, I am trying to carry out a calculation for an overspill of a damn. When it overflows 1.21x10^8 1s1 exits, how can I show that the mass of water leaving the lake is 1.22x10^8 kg? Density  1012 kg m3 g = 9.81ms2 Thanks. Last edited by skipjack; February 13th, 2019 at 06:26 AM. 
February 13th, 2019, 05:41 AM  #4  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,138 Thanks: 872 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
Can you please post the whole question? Dan Last edited by skipjack; February 13th, 2019 at 06:26 AM.  
February 13th, 2019, 05:57 AM  #5  
Math Team Joined: Jul 2011 From: Texas Posts: 2,883 Thanks: 1503  Quote:
$(1.21 \times 10^8 \, L/s) \, \cdot (10^{3} \, m^3/L) \, \cdot (1012 \, kg/m^3) \, = 1.22 \times 10^8 \, kg/s$ ... note the water leaving the lake is a rate of kg per second, not just kg. Last edited by skipjack; February 13th, 2019 at 06:25 AM.  

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