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January 11th, 2019, 05:41 AM  #1 
Member Joined: Feb 2018 From: Iran Posts: 30 Thanks: 3 
An arrow is shot upward on a planet. Its height (in meters) after t seconds is given by h(t) = 60t – 0.6t^2. a. At what time will the arrow reach the top? b. With what velocity will the arrow hit the ground? Last edited by skipjack; January 12th, 2019 at 03:41 AM. 
January 11th, 2019, 08:24 AM  #2 
Senior Member Joined: Dec 2015 From: iPhone Posts: 436 Thanks: 68 
(a) $\displaystyle h’(t)=0$

January 12th, 2019, 10:22 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,370 Thanks: 2007 
As h(t) = 1500  .6(50  t)², its maximum value occurs when t = 50. When the arrow hits the ground, it will have a velocity that is directed downward and has magnitude 60 meters per second. 

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change, derivatives, rate 
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