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January 11th, 2019, 06:41 AM   #1
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An arrow is shot upward on a planet. Its height (in meters) after t seconds is given by h(t) = 60t – 0.6t^2.
a. At what time will the arrow reach the top?
b. With what velocity will the arrow hit the ground?

Last edited by skipjack; January 12th, 2019 at 04:41 AM.
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January 11th, 2019, 09:24 AM   #2
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(a) $\displaystyle h’(t)=0$
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January 12th, 2019, 11:22 AM   #3
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As h(t) = 1500 - .6(50 - t)², its maximum value occurs when t = 50.

When the arrow hits the ground, it will have a velocity that is directed downward and has magnitude 60 meters per second.
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