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 January 11th, 2019, 05:41 AM #1 Member   Joined: Feb 2018 From: Iran Posts: 56 Thanks: 3 An arrow is shot upward on a planet. Its height (in meters) after t seconds is given by h(t) = 60t – 0.6t^2. a. At what time will the arrow reach the top? b. With what velocity will the arrow hit the ground? Last edited by skipjack; January 12th, 2019 at 03:41 AM.
 January 11th, 2019, 08:24 AM #2 Senior Member   Joined: Dec 2015 From: somewhere Posts: 734 Thanks: 98 (a) $\displaystyle h’(t)=0$
 January 12th, 2019, 10:22 AM #3 Global Moderator   Joined: Dec 2006 Posts: 21,034 Thanks: 2269 As h(t) = 1500 - .6(50 - t)², its maximum value occurs when t = 50. When the arrow hits the ground, it will have a velocity that is directed downward and has magnitude 60 meters per second.

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