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December 26th, 2018, 09:17 PM   #1
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Complex number equating

Hello Every one,
It was tying to equate complex number summation. It looks easy, but took me a while to solve it . would you help me please? It is attached as image as follows:
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File Type: png equate.PNG (4.7 KB, 20 views)

Last edited by Fikadu; December 26th, 2018 at 09:20 PM.
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December 27th, 2018, 01:23 PM   #2
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Move Z1ZL to left side?
Thanks from topsquark

Last edited by mathman; December 27th, 2018 at 01:26 PM.
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December 27th, 2018, 02:43 PM   #3
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Quote:
Originally Posted by Fikadu View Post
Hello Every one,
It was tying to equate complex number summation. It looks easy, but took me a while to solve it . would you help me please? It is attached as image as follows:
Sorry, I guess you didn't get my question. I want to express Zm and ZL in terms of Z1 and Z2 by rearranging. Let it be (Zm*ZL)/ (Zm + ZL) = (Z1 -Z2)/ (Z1*Z2). I need in such a way.

Thank you a lot
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December 27th, 2018, 02:43 PM   #4
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Quote:
Originally Posted by mathman View Post
Move Z1ZL to left side?
Sorry, I guess you didn't get my question. I want to express Zm and ZL in terms of Z1 and Z2 by rearranging. Let it be (Zm*ZL)/ (Zm + ZL) = (Z1 -Z2)/ (Z1*Z2). I need in such a way.

Thank you a lot
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December 27th, 2018, 03:46 PM   #5
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Quote:
Originally Posted by Fikadu View Post
I want to express Zm and ZL in terms of Z1 and Z2 by rearranging.
Let it be (Zm*ZL)/ (Zm + ZL) = (Z1 -Z2)/ (Z1*Z2).
Boy oh boy...what a headache!

At least, shorten the darn thing:
a = ZL, b = ZM, c = Z1, d = Z2

So the original equation is:
bc + ab + bd = ac + cd

However, converting that to what you're trying for
seems impossible to me.....
Thanks from topsquark and idontknow
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