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October 26th, 2018, 03:13 AM  #1 
Member Joined: Feb 2018 From: England Posts: 61 Thanks: 0  Loglinear
Hi All, Please see attached image of a loglinear graph. Find the number of bacteria at 19s? Number of bacteria = 10x, where x? Thanks all. 
October 26th, 2018, 08:06 AM  #2 
Member Joined: Feb 2018 From: England Posts: 61 Thanks: 0 
Attached pic.

October 30th, 2018, 07:03 AM  #3  
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 126  Quote:
At 19sec N=8000 Not sure what you are asking: At t=2sec N=20 The number of bacteria grow by a factor of 10 every 7sec  
October 30th, 2018, 08:59 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 20,926 Thanks: 2205 
At 19 seconds, N appears to be about 6400, which would suggest N = 10*640^(t/19) approximately.

October 30th, 2018, 10:26 AM  #5  
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 126  Quote:
N=6400. You are plotting LogN but labelling the points N. So, for example, if N=3000, you plot Log3000=3 but you label the point 3000.  
October 30th, 2018, 08:40 PM  #6 
Global Moderator Joined: Dec 2006 Posts: 20,926 Thanks: 2205 
N is plotted, but using a logarithmic scale. The labels are consistent with that. Of course, the resulting line has the same appearance as would be obtained by plotting log(N) on a linear scale.


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