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October 26th, 2018, 03:13 AM   #1
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Log-linear

Hi All,

Please see attached image of a log-linear graph.

Find the number of bacteria at 19s?
Number of bacteria = 10x, where x?

Thanks all.
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 Log-linear.jpg (5.3 KB, 10 views)

October 26th, 2018, 08:06 AM   #2
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Attached pic.
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 Log Linear 2.zip (21.2 KB, 3 views)

October 30th, 2018, 07:03 AM   #3
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Quote:
 Originally Posted by NAC54321 Please see attached image of a log-linear graph. Find the number of bacteria at 19s? Number of bacteria = 10x, where x?

At 19sec N=8000

Not sure what you are asking:
At t=2sec N=20
The number of bacteria grow by a factor of 10 every 7sec

 October 30th, 2018, 08:59 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,926 Thanks: 2205 At 19 seconds, N appears to be about 6400, which would suggest N = 10*640^(t/19) approximately.
October 30th, 2018, 10:26 AM   #5
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Quote:
 Originally Posted by skipjack At 19 seconds, N appears to be about 6400, which would suggest N = 10*640^(t/19) approximately.
6400 is more accurate. The lines are quite faint.

N=6400. You are plotting LogN but labelling the points N.

So, for example, if N=3000, you plot Log3000=3 but you label the point 3000.

 October 30th, 2018, 08:40 PM #6 Global Moderator   Joined: Dec 2006 Posts: 20,926 Thanks: 2205 N is plotted, but using a logarithmic scale. The labels are consistent with that. Of course, the resulting line has the same appearance as would be obtained by plotting log(N) on a linear scale.

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