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October 25th, 2018, 06:03 AM  #1 
Member Joined: Feb 2018 From: England Posts: 61 Thanks: 0  Energy required?
Hi All, Can someone help me with the following required formula: Ammonia NH3 is a covalently bonded molecule, made up of three HN bonds. Calculate the energy required to break all of the bonds in 72 grammes (g) Use the following values: • HN bond energy = 388kJ mol1 •Atomic mass of nitrogen = 14.007 g mol1 •Atomic mass of hydrogen = 1.008 g mol1 Answer in kilojoules (kJ) . Thanks. 
October 29th, 2018, 10:13 AM  #2 
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 125 
14+3x1=17g/M Bond Energy = 3x388 kJ/M 3x388kJ/M x 1M/17g=68.5kJ/g x 72g 

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