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October 25th, 2018, 06:03 AM   #1
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Energy required?

Hi All,

Can someone help me with the following required formula:


Ammonia NH3 is a covalently bonded molecule, made up of three H-N bonds.

Calculate the energy required to break all of the bonds in 72 grammes (g)

Use the following values:

• H-N bond energy = 388kJ mol-1
•Atomic mass of nitrogen = 14.007 g mol-1
•Atomic mass of hydrogen = 1.008 g mol-1


Answer in kilojoules (kJ) .

Thanks.
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October 29th, 2018, 10:13 AM   #2
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14+3x1=17g/M
Bond Energy = 3x388 kJ/M
3x388kJ/M x 1M/17g=68.5kJ/g x 72g
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